Question

Jsonlint显示此JSON对象有效：

 [{"obj":{"markers":"[{\"k\":47.040182144806664,\"B\":0.52734375},{\"k\":50.90303283111257,\"B\":10.37109375},{\"k\":52.53627304145945,\"B\":-1.7578125},{\"k\":41.77131167976406,\"B\":-6.591796875}]","path":"[[47.040182144806664,0.52734375],[50.90303283111257,10.37109375],[52.53627304145945,-1.7578125],[41.77131167976406,-6.591796875]]"}}]

我尝试使用k，B和路径元素访问标记，但它始终设置为未定义。这是我的代码：

 try {

       var jsonData = JSON.parse(myJson);
       console.log(jsonData.obj[0].markers[0].k);
     }
 catch (e) {
             console.error("Parsing error:", e);
           }

有人能告诉我如何正确访问我的JSON对象的元素吗？谢谢你的帮助。

Answer 1

创建此字符串时必定出错。是的，它是有效的JSON，但它的格式与您想象的不同，因为您可以转义控制字符，例如"和[，]。

请尝试使用此字符串：

[
   {
      "obj":{
         "markers":[
            {
               "k":47.040182144806664,
               "B":0.52734375
            },
            {
               "k":50.90303283111257,
               "B":10.37109375
            },
            {
               "k":52.53627304145945,
               "B":-1.7578125
            },
            {
               "k":41.77131167976406,
               "B":-6.591796875
            }
         ],
         "path":[
            [
               47.040182144806664,
               0.52734375
            ],
            [
               50.90303283111257,
               10.37109375
            ],
            [
               52.53627304145945,
               -1.7578125
            ],
            [
               41.77131167976406,
               -6.591796875
            ]
         ]
      }
   }
]

而不是你的字符串：

[
   {
      "obj":{
         "markers":"[{\"k\":47.040182144806664,\"B\":0.52734375},{\"k\":50.90303283111257,\"B\":10.37109375},{\"k\":52.53627304145945,\"B\":-1.7578125},{\"k\":41.77131167976406,\"B\":-6.591796875}]",
         "path":"[[47.040182144806664,0.52734375],[50.90303283111257,10.37109375],[52.53627304145945,-1.7578125],[41.77131167976406,-6.591796875]]"
      }
   }
]

Answer 2

我可以告诉你两个问题：

一，是的，它是有效的Json，但标记和路径对象值用数字引号括起来：

"markers":"[{\"k\":47.040182144806664,\"B\":0.52734375},{\"k\":50.90303283111257,\"B\":10.37109375},{\"k\":52.53627304145945,\"B\":-1.7578125},{\"k\":41.77131167976406,\"B\":-6.591796875}]",
"path":"[[47.040182144806664,0.52734375],[50.90303283111257,10.37109375],[52.53627304145945,-1.7578125],[41.77131167976406,-6.591796875]]"

你最想要的是：

"markers":[{"k":47.040182144806664,"B":0.52734375},{"k":50.90303283111257,"B":10.37109375},{"k":52.53627304145945,"B":-1.7578125},{"k":41.77131167976406,"B":-6.591796875}],

"path":[[47.040182144806664,0.52734375],[50.90303283111257,10.37109375],[52.53627304145945,-1.7578125],[41.77131167976406,-6.591796875]]

但是考虑到上述情况，也没有逃避标记的k和b对象名称\＆＃34; k \＆＃34;应该是＆＃34; k＆＃34;：

所以完成编辑的JSON看起来像这样：

[{"obj":{"markers":[{"k":47.040182144806664,"B":0.52734375},{"k":50.90303283111257,"B":10.37109375},{"k":52.53627304145945,"B":-1.7578125},{"k":41.77131167976406,"B":-6.591796875}],"path":[[47.040182144806664,0.52734375],[50.90303283111257,10.37109375],[52.53627304145945,-1.7578125],[41.77131167976406,-6.591796875]]}}]

使用多个数据进行JSON解析

2 个答案: