Question

我正在尝试实现一个允许输出csv文件的通用方法

public static void WriteToCsv<T>(List<T> list) where T : new()
    {
        const string attachment = "attachment; filename=PersonList.csv";
        HttpContext.Current.Response.Clear();
        HttpContext.Current.Response.ClearHeaders();
        HttpContext.Current.Response.ClearContent();
        HttpContext.Current.Response.AddHeader("content-disposition", attachment);
        HttpContext.Current.Response.ContentType = "text/csv";
        HttpContext.Current.Response.AddHeader("Pragma", "public");                   

        bool isFirstRow = true;
        foreach (T item in list)
        {                
            //Get public properties
            PropertyInfo[] propertyInfo = item.GetType().GetProperties();

            while (isFirstRow)
            {
                WriteColumnName(propertyInfo);
                isFirstRow = false;
            }

            Type type = typeof (T);

            StringBuilder stringBuilder = new StringBuilder();

            foreach (PropertyInfo info in propertyInfo)
            {
                   //string value ???? I am trying to get the value of the property info for the item object

            }                
            HttpContext.Current.Response.Write(stringBuilder.ToString());
            HttpContext.Current.Response.Write(Environment.NewLine);                
        }
        HttpContext.Current.Response.End();
    }

但是我无法获得对象属性的值

有什么建议吗？

由于

Answer 1

像这样：

object value = info.GetValue(item, null);

Answer 2

你去..

PropertyInfo[] propertyInfo = item.GetType().GetProperties(); 
var val = propertyInfo.GetValue(item, null);

反思和泛型获得财产的价值

2 个答案: