我的索引页面有2个下拉列表。第二个下拉列表取决于第一个下拉列表,在从第二个列表中选择一个值后,将根据所选值通过数据库表执行搜索,然后显示匹配结果。我想要的是得到显示的结果(在这种情况下,纬度和经度对应的结果)应该在谷歌地图上显示
到目前为止的代码
包含下拉列表的主页上的代码,将显示地图
<div class="showsearch" id="gmap_canvas"> //place where the ,ap should get displayed
</div>
执行搜索以显示结果的代码,也应该适用于地图
<?php
include("connection.php");
if(isset($_POST['fname']))
{
$fname = mysqli_real_escape_string($con, $_POST['fname']);
$sql1 = 'SELECT * FROM features_for_office WHERE fname LIKE "%'.$fname.'%"';
$result = mysqli_query($con, $sql1);
if (mysqli_num_rows($result) > 0)
{
while($row = mysqli_fetch_assoc($result))
{
$latitude= $row["latitude"];
$longitude= $row["longitude"];
}
?>
<!-- JavaScript to show google map -->
<div class="showsearch" id="gmap_canvas"></div>
<script>
function init_map(lat,lang) {
var myOptions = {
zoom: 14,
center: new google.maps.LatLng(lat, lang),
mapTypeId: google.maps.MapTypeId.ROADMAP
};
map = new google.maps.Map(document.getElementById("gmap_canvas"), myOptions);
marker = new google.maps.Marker({
map: map,
position: new google.maps.LatLng(<?php echo $latitude; ?>, <?php echo $longitude; ?>)
});
/*infowindow = new google.maps.InfoWindow({
content: "<?php echo $formatted_address; ?>"
});*/
google.maps.event.addListener(marker, "click", function () {
infowindow.open(map, marker);
});
infowindow.open(map, marker);
}
function loadCoordinates(){
var latitude;
var longitude;
$('.showsearch').blur(function() {
$.ajax({
type: "GET",
dataType: "json",
url: "get_search_data.php",
data: "name="+$(this).val(),
success: function(json){
$('#number').val(json.num);
}
});
});
//call the function once coordinates are available from the server/
//init_map must be called from the call back of ajax function
init_map(latitude,longitude);
}
//instead of init_map call the loadCoordinates to get the values from server
google.maps.event.addDomListener(window, 'load', loadCoordinates);
</script>
<?php }
else
{
echo "0 results";
}
mysqli_close($con);
}
?>
虽然我得到纬度和经度的值,但我无法在特定纬度和经度上显示地图以及标记。任何帮助将不胜感激
答案 0 :(得分:0)
考虑到您正在从服务器检索坐标值,您可以修改地图渲染代码,以根据通过AJAX从服务器检索的纬度 - 经度值加载地图。在您要显示地图的页面上,您可以使用下面提到的代码。
<div class="showsearch" id="gmap_canvas"> </div>
<script type="text/javascript" src="http://maps.google.com/maps/api/js?sensor=false"></script>
<script type="text/javascript">
function init_map(lat,lang) {
var myOptions = {
zoom: 14,
center: new google.maps.LatLng(lat, lang),
mapTypeId: google.maps.MapTypeId.ROADMAP
};
map = new google.maps.Map(document.getElementById("gmap_canvas"), myOptions);
marker = new google.maps.Marker({
map: map,
position: new google.maps.LatLng(<?php echo $latitude; ?>, <?php echo $longitude; ?>)
});
/*infowindow = new google.maps.InfoWindow({
content: "<?php echo $formatted_address; ?>"
});*/
google.maps.event.addListener(marker, "click", function () {
infowindow.open(map, marker);
});
infowindow.open(map, marker);
}
function loadCoordinates(){
$('.showsearch').blur(function() {
$.ajax({
type: "GET",
dataType: "json",
url: "get_search_data.php",
data: "name="+$(this).val(),
success: function(json){
var latitude;
var longitude;
latitude = LATITUDE_VALUE_FROM_SERVER;
longitude = LONGTITUDE_VALUE_FROM_SERVER;
init_map(latitude,longitude);
}
});
});
}
//instead of init_map call the loadCoordinates to get the values from server
google.maps.event.addDomListener(window, 'load', loadCoordinates);
</script>
您需要使用ajax调用从服务器检索坐标值,并在ajax函数的回调中调用该函数来加载地图。