我必须为基于数组的数据库编写一个程序,该程序允许用户输入新数据,更新现有数据,删除条目和查看条目列表。需求是一个名为DATE的结构,一个名为CustData的结构,用于保存用户数据,一个类型为CustData的数组,大小为10,需要一个单独的函数来输入,更新,删除和显示客户数据。它还需要使用while循环来初始化数组中的每个索引,并将所有内容初始化为0.我编写了一个粗略的程序但是我工作的越多,我就越觉得我做错了。到目前为止,我已经开始工作,它允许我添加多个条目而不覆盖以前的条目,但我似乎无法限制我可以输入的条目数。我也有正确的条目显示。非常感谢任何可以提供的帮助,下面是我的程序到目前为止,一些数据输入部分被注释掉,以便更容易测试。我对此表示歉意,这是用C ++编写的,用visual studio 2013编写。
#include <iostream>
#include <fstream>
#include <iomanip>
#include <string>
using namespace std;
struct Date
{
int month,
day,
year;
};
struct cust
{
int ID;
string name;
string address;
string city;
string state;
string zip;
string phone;
double balance;
Date lastpayment;
};
const int SIZE = 10;
int menuchoice;
int num = 0;
int i;
void showmenu();
void funcentercustdata(cust[], int);
void funcupdatecustdata();
void funcdeletecustdata();
void funcdisplaycustdata(cust[], int);
cust custdb[SIZE];
int main()
{
cout << "Welcome to Michael's Marvelous Database Contrabulator!\n";
cout << setw(10) << "Customer Database\n\n\n";
showmenu();
int index;
for (index = 0; index < SIZE; index++)
{
custdb[index].ID = 0;
custdb[index].name = "";
custdb[index].address = "";
custdb[index].city = "";
custdb[index].state = "";
custdb[index].zip = "";
custdb[index].phone = "";
custdb[index].balance = 0.00;
custdb[index].lastpayment.month = 0;
custdb[index].lastpayment.day = 0;
custdb[index].lastpayment.year = 0;
}
return 0;
}
void showmenu()
{
cout << "\n\n1) Enter new customer data.\n";
cout << "2) Update customer data.\n";
cout << "3) Delete customer data.\n";
cout << "4) Display Customer data.\n";
cout << "5) Quit the program.\n\n";
cout << "Please enter your choice: ";
cin >> menuchoice;
do
{
switch (menuchoice)
{
case 1:
funcentercustdata(custdb, SIZE);
showmenu();
break;
case 2:
funcupdatecustdata();
showmenu();
break;
case 3:
funcdeletecustdata();
showmenu();
break;
case 4:
funcdisplaycustdata(custdb, SIZE);
showmenu();
break;
case 5:
cout << "Thank you and have a nice day!\n";
break;
default:
cout << "Please enter a correct choice\n";
cin >> menuchoice;
break;
}
} while (menuchoice != 5);
}
void funcentercustdata(cust custinfo[], int size)
{
if (custinfo[i].ID != 0)
{
i++;
cout << "\n\nEnter ID: ";
cin >> custinfo[i].ID;
cout << "Enter name: ";
cin.ignore(0);
cin >> custinfo[i].name;
/* cout << "Enter address: ";
cin.ignore(0);
cin>>custinfo[i].address;
cout << "Enter city: ";
cin.ignore(0);
cin>>custinfo[i].city;
cout << "Enter state: ";
cin.ignore(0);
cin>>custinfo[i].state;
cout << "Enter zip: ";
cin.ignore(0);
cin>>custinfo[i].zip;
cout << "Enter phone number (###-###-####): ";
cin.ignore(0);
cin>>custinfo[i].phone;
cout << "Enter balance: ";
cin >> custinfo[i].balance;
cout << "Enter last payment (mo day year, e.g. 11 17 2014): ";
cin >> custinfo[i].lastpayment.month >> custinfo[i].lastpayment.day
>> custinfo[i].lastpayment.year;
cin.ignore(1);
// }*/
cout << "Customers successfully added.\n";
}
else if (custinfo[i].ID != 0 && custinfo[i].ID >= 4)
{
cout << "No further inputs allowed\n";
}
else
{
cout << "\n\nEnter ID: ";
cin >> custinfo[i].ID;
cout << "Enter name: ";
cin.ignore(0);
cin >> custinfo[i].name;
/* cout << "Enter address: ";
cin.ignore(0);
cin>>custinfo[i].address;
cout << "Enter city: ";
cin.ignore(0);
cin>>custinfo[i].city;
cout << "Enter state: ";
cin.ignore(0);
cin>>custinfo[i].state;
cout << "Enter zip: ";
cin.ignore(0);
cin>>custinfo[i].zip;
cout << "Enter phone number (###-###-####): ";
cin.ignore(0);
cin>>custinfo[i].phone;
cout << "Enter balance: ";
cin >> custinfo[i].balance;
cout << "Enter last payment (mo day year, e.g. 11 17 2014): ";
cin >> custinfo[i].lastpayment.month >> custinfo[i].lastpayment.day
>> custinfo[i].lastpayment.year;
cin.ignore(1);
// }*/
cout << "Customers successfully added.\n";
}
}
void funcupdatecustdata()
{
cout << "insert function 2\n\n";
}
void funcdeletecustdata()
{
cout << "insert function 3\n\n";
}
void funcdisplaycustdata(cust custinfo[], int size)
{
for (int i = 0; i < size; i++)
{
if (custinfo[i].ID == 0)
cout << " ";
else if (custinfo[i].ID != 0)
{
cout << "\n\nClient ID: " << custinfo[i].ID << endl;
cout << "Client name: " << custinfo[i].name << endl;
/* cout << "Client address: " << custinfo[i].name << endl;
cout << "Client city: " << custinfo[i].name << endl;
cout << "Client state: " << custinfo[i].name << endl;
cout << "Client zip: " << custinfo[i].name << endl;
cout << "Client phone: " << custinfo[i].name << endl;*/
cout << "Client balance: " << custinfo[i].balance << endl;
cout << "Client last deposit: " << custinfo[i].lastpayment.month << "/" <<
custinfo[i].lastpayment.day << "/" << custinfo[i].lastpayment.year << endl;
}
}
}
答案 0 :(得分:1)
您已经就程序中的问题提出了多个问题。所以我将看看第一个问题:
我似乎无法限制我可以输入的条目数
首先,您的代码存在一些根本性缺陷。一个缺陷就是showmenu()
函数重复调用showmenu()
。这是一个递归调用,完全没必要。想象一下,如果您的程序或类似程序以这种方式构建,必须每天24小时运行,并且添加了数千个条目。您将使用所有递归调用来彻底清除堆栈。所以这必须修复。
其次,showmenu()
,至少对我来说,应该做它所说的,那就是&#34;显示菜单&#34;。它不应该是处理输入。在单独的函数中处理输入。
这是该程序的更模块化版本:
#include <iostream>
void processChoice(int theChoice);
void showmenu();
void addCustomer();
void deleteCustomer();
int getMenuChoice();
int customerCount = 0;
int main()
{
cout << "Welcome to Michael's Marvelous Database Contrabulator!\n";
cout << setw(10) << "Customer Database\n\n\n";
int choice = 0;
do
{
showmenu();
choice = getMenuChoice();
if (choice != 5)
processChoice(choice);
} while (choice != 5);
}
void showmenu()
{
cout << "\n\n1) Enter new customer data.\n";
cout << "2) Update customer data.\n";
cout << "3) Delete customer data.\n";
cout << "4) Display Customer data.\n";
cout << "5) Quit the program.\n\n";
}
int getMenuChoice()
{
int theChoice;
cout << "Please enter your choice: ";
cin >> theChoice;
return theChoice;
}
void processChoice(int theChoice)
{
switch (theChoice)
{
case 1:
addCustomer();
break;
//...
case 3:
deleteCustomer();
break;
}
}
void addCustomer()
{
if ( customerCount < 10 )
{
// add customer
// put your code here to add the customer
//...
// increment the count
++customerCount;
}
}
void deleteCustomer()
{
if ( customerCount > 0 )
{
// delete customer
--customerCount;
}
}
这是跟踪客户数量的基本概要。代码组织和模块化是关键。当前条目数的计数可以通过addCustomer
和deleteCustomer
函数递增或递减。另请注意在add/deleteCustomer()
中完成的测试。
在main()
函数中,请注意do-while循环及其设置方式。 showMenu
函数显示自己,getMenuChoice
函数获取选择并返回所选的数字
如果选择不是5,则处理请求。如果是5,则while
的{{1}}部分会将您踢出处理,否则您将从顶部开始(do-while
,showMenu
等)。这可以避免原始代码正在进行的递归调用。