Question

没有显示错误，代码也无效。数据库也没有任何变化。当我打开我的页面insert.php并填写详细信息时，只需重置表单。

// insert.php

<html>
    <head>
        <title>Insert Record</title>
    </head>
    <body>
        <form action="insert.php" method="post">
        Name: <input type="text" name="name"><br><p />
        Roll No.: <input type="text" name="rollno"><br><p />
        Duration: <input type="text" name="duration"><br><p />
        Course: <input type="text" name="course"><br><p />
        Date of Birth: <input type="text" name="dob"><br><p />
        Photo: <input type="file" name="image"><br><p />
        <input type="submit" name="submit" value="Submit">
    </form>

    <?php
    error_reporting(0);


    //connection
    $servername = "localhost";
    $username = "root";
    $password = "";
    $dbname = "vision";

    // Create connection
    $conn = new mysqli($servername, $username, $password,$dbname);

    // Check connection
    if ($conn->connect_error) {
        die("Connection failed: " . $conn->connect_error);
    } 

    $file = $_FILES["image"]["tmp_name"];
     if (!isset($file))
         {echo "Please Select an Image";}
        else
        { 
            $name = $_POST["name"];
            $rollno = $_POST["rollno"];
            $duration = $_POST["duration"];
            $dob = $_POST["dob"];
            $course = $_POST["course"];
            $image=addslashes(file_get_contents($_FILES["image"]["tmp_name"]));
            //$image_name= addslashes($_FILES["image"]["name"]);
            $image_size=  getimagesize($_FILES["image"]["tmp_name"]);

    //inserting data

            if($image_size==FALSE)
                {echo "That's not an Image";}
            else
            {       
                $sql = mysqli_query($conn,"INSERT INTO record(rollno,name,duration,dob,course,image)VALUES('$rollno','$name','$duration','$dob','$course','$image')");

                if($conn->query($sql) == TRUE)
                {
                    echo "<br>Input data is succeed";
                } 
                else
                {
                    echo "<br>Input data is fail";
                }
            }
        }
    ?>
    </body>
    </html>

Answer 1

这是因为当没有图像存在时将不会显示任何图像，并且永远不会有图像。如果要发布图片，则需要添加enctype代码multipart/form-data。

更改

<form action="insert.php" method="post">

要

<form action="test.php" enctype="multipart/form-data" method="post">

如果您向表单添加图片，则会显示$sql = mysqli_query($conn,"INS....行。

Answer 2

使用： -

<form action="test.php" enctype="multipart/form-data" method="post">

PHP数据库中的MySQL数据插入没有显示错误

2 个答案: