我为cloudkit设置了订阅通知。这是我的代码:
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"TRUEPREDICATE"];
CKSubscription *subscription = [[CKSubscription alloc]
initWithRecordType:recordType
predicate:predicate
options:CKSubscriptionOptionsFiresOnRecordCreation];
CKNotificationInfo *notificationInfo = [CKNotificationInfo new];
notificationInfo.alertLocalizationKey =@"New record in cloudKit";
notificationInfo.shouldBadge = YES;
notificationInfo.soundName = UILocalNotificationDefaultSoundName;
notificationInfo.shouldSendContentAvailable = YES;
subscription.notificationInfo = notificationInfo;
CKContainer *container = [CKContainer defaultContainer];
CKDatabase *publicDatabase = [container publicCloudDatabase];
[publicDatabase saveSubscription:subscription
completionHandler:^(CKSubscription *subscription, NSError *error) {
if (!error)
{
NSLog(@"no error");
}
else
{
NSLog(@"error%@", error);
}
}];
并且工作得很好。问题是徽章,它们看起来像是cloudKit没有重置徽章编号并且即使我将徽章计数设置为零也会不断增加。
- (void)applicationDidBecomeActive:(UIApplication *)application
{
application.applicationIconBadgeNumber = 0;
}
当应用收到新通知时,从0到5(每个新通知增加1,下一次将是6)
你们中的任何人都知道如何从cloudkit跟踪正确的徽章数量(在Objective-C中)
答案 0 :(得分:8)
这是CloudKit won't reset my badge count to 0
的副本答案是: 处理完通知后,您需要执行CKModifyBadgeOperation。
这是我的Swift函数,我将所有通知标记为已读时调用。我将操作添加到defaultContainer而不是仅仅启动它 - 我不知道这会有什么不同。
func resetBadgeCounter() {
let badgeResetOperation = CKModifyBadgeOperation(badgeValue: 0)
badgeResetOperation.modifyBadgeCompletionBlock = { (error) -> Void in
if error != nil {
println("Error resetting badge: \(error)")
}
else {
UIApplication.sharedApplication().applicationIconBadgeNumber = 0
}
}
CKContainer.defaultContainer().addOperation(badgeResetOperation)
}
答案 1 :(得分:1)
这会有所帮助。
CKModifyBadgeOperation *badgeResetOperation = [[CKModifyBadgeOperation alloc] initWithBadgeValue:0];
[badgeResetOperation setModifyBadgeCompletionBlock:^(NSError * operationError) {
if (!operationError) {
[UIApplication sharedApplication].applicationIconBadgeNumber = 0;
}
}];
[[CKContainer defaultContainer] addOperation:badgeResetOperation];