Question

我想按年份对此进行分组：

[{"_id"=>{"year"=>2013, "month"=>8}, "count"=>69605},
 {"_id"=>{"year"=>2013, "month"=>7}, "count"=>60620},
 {"_id"=>{"year"=>2013, "month"=>12}, "count"=>56026},
 {"_id"=>{"year"=>2014, "month"=>5}, "count"=>55067},
 {"_id"=>{"year"=>2014, "month"=>4}, "count"=>51313},
 {"_id"=>{"year"=>2013, "month"=>11}, "count"=>48044},
 {"_id"=>{"year"=>2014, "month"=>8}, "count"=>43802},
 {"_id"=>{"year"=>2014, "month"=>1}, "count"=>40428},
 {"_id"=>{"year"=>2014, "month"=>3}, "count"=>39564},
 {"_id"=>{"year"=>2013, "month"=>9}, "count"=>35682},
 {"_id"=>{"year"=>2013, "month"=>10}, "count"=>34073},
 {"_id"=>{"year"=>2014, "month"=>2}, "count"=>32774},
 {"_id"=>{"year"=>2014, "month"=>6}, "count"=>30772},
 {"_id"=>{"year"=>2014, "month"=>9}, "count"=>17347},
 {"_id"=>{"year"=>2014, "month"=>7}, "count"=>5319},
 {"_id"=>{"year"=>2013, "month"=>6}, "count"=>4468},
 {"_id"=>{"year"=>2013, "month"=>5}, "count"=>2978},
 {"_id"=>{"year"=>2013, "month"=>4}, "count"=>2498},
 {"_id"=>{"year"=>2013, "month"=>3}, "count"=>360},
 {"_id"=>{"year"=>2013, "month"=>1}, "count"=>112},
 {"_id"=>{"year"=>2012, "month"=>12}, "count"=>88},
 {"_id"=>{"year"=>2013, "month"=>2}, "count"=>28},
 {"_id"=>{"year"=>2015, "month"=>11}, "count"=>1}]

有人可以帮助我吗？

Answer 1

试试这个

Your_Array.group_by{|a| a["_id"]["year"]}

Answer 2

您的问题已解决，请查看以下解决方案

Your_array.group_by { |d| d['_id']['year'] }

Answer 3

Enumerable#reduce来救援。假设数据存储在数据变量中：

data.reduce({}) { |memo, item| 
  (memo[item['_id']['year']] ||= []) << item; 
  memo 
}

# => {
#  2012 => [
#    [0] {
#        "_id" => {
#        "month" => 12,
#         "year" => 2012
#      },
#      "count" => 88
#    }
#  ],
#  2013 => [
#    [ 0] {
# ...

可能就是你要找的东西。是否要生成重组数据，只需修改被调用者。

Answer 4

我想这对你有用：

array.group_by{|a| a["_id"]["year"]}.values

Answer 5

使用Enumerable#group_by。

array.group_by { |record| record['_id']['year'] }

#=> {2013=>
#  [{"_id"=>{"year"=>2013, "month"=>8}, "count"=>69605},
#   ...
#   {"_id"=>{"year"=>2013, "month"=>2}, "count"=>28}],
# 2014=>
#  [{"_id"=>{"year"=>2014, "month"=>5}, "count"=>55067},
#   ...
#   {"_id"=>{"year"=>2014, "month"=>7}, "count"=>5319}],
# 2012=>[{"_id"=>{"year"=>2012, "month"=>12}, "count"=>88}],
# 2015=>[{"_id"=>{"year"=>2015, "month"=>11}, "count"=>1}]}

Answer 6

使用Enumerable#group_by

grouped_array = array.group_by {|record| record["_id"]["year"]}

使用Enumerable#sort_by对记录进行排序

sorted_array = grouped_array.sort_by{|year, records| year}
formated_hash = sorted_array.to_h

这将按年份的升序值排序。如果您想按降序排序，请使用Array.reverse

desc_sorted_array = sorted_array.reverse
formated_hash = desc_sorted_array.to_h

如何在Ruby中使用此类型数据进行group_by year

6 个答案: