Question

如果从GtkTreeView连续“右键单击”，我想显示一个弹出菜单。只有在第一列（或特定列）中“右键单击”时，弹出菜单才会显示？

我已经使用了代码，但是整个行的播放菜单。

gboolean
on_tree_view_button_pressed(GtkWidget *treeview, GdkEventButton *event, gpointer data)
{

    if (event->type == GDK_BUTTON_PRESS && event->button == 3) {
        GtkTreePath *path;

        selection = gtk_tree_view_get_selection(GTK_TREE_VIEW(treeview));
        if (gtk_tree_view_get_path_at_pos(GTK_TREE_VIEW(treeview),
                                                      event->x, event->y,
                                              &path, NULL, NULL, NULL)) {
        gtk_tree_selection_unselect_all(selection);
        gtk_tree_selection_select_path(selection, path);
        gtk_tree_path_free(path);
        }

        do_popup_menu(treeview, event, data);

        return TRUE;
    }

    return FALSE;
}

我有3列的GtkTreeView，我想只显示第一列的菜单

Answer 1

您已拨打gtk_tree_view_get_path_at_pos。此功能还可以获取鼠标下的树视图列。不要为column参数传递NULL，而是确保获取列并将其与所需列进行比较：

if (event->type == GDK_BUTTON_PRESS && event->button == 3) {
    GtkTreePath *path;
    GtkTreeViewColumn *column;

    selection = gtk_tree_view_get_selection(GTK_TREE_VIEW(treeview));
    if (!gtk_tree_view_get_path_at_pos(GTK_TREE_VIEW(treeview),
                                       event->x, event->y,
                                       &path, &column, NULL, NULL))
        // if we can't find path at pos, we surely don't
        // want to pop up the menu
        return FALSE;

    if (column != gtk_tree_view_get_column(GTK_TREE_VIEW(treeview), 0)) {
        // wrong column, don't bother
        gtk_tree_path_free(path);
        return FALSE;
    }

    gtk_tree_selection_unselect_all(selection);
    gtk_tree_selection_select_path(selection, path);
    gtk_tree_path_free(path);

    do_popup_menu(treeview, event, data);

    return TRUE;
}

右键单击GtkTreeView中的上下文菜单（仅适用于指定列）

1 个答案: