问：这个java代码有什么问题吗？

Question

package firstproject;
import java.util.Scanner;

public class walkthrough {
    public static void main(String[] args){
        Scanner in = new Scanner(System.in);
        String a = in.nextLine();       
        System.out.println("Welcome home!");
        System.out.println("Would you like to go in?");
        String door = a;
        if(a.equals(door));
        System.out.println("Your are now in the house what now?");
    }        
}

Answer 1

此：

if(a.equals(door));
    System.out.println("Your are now in the house what now?");

是：

if(a.equals(door)) { }
System.out.println("Your are now in the house what now?");

无论if条件中表达式的值如何，都将执行print语句。

删除;条件后的多余if。

另请遵循惯例并将您的班级重命名为大写字母。

Answer 2

if语句后的分号。改变;在{

Answer 3

if(a.equals(door)); // semicolon - statement
        System.out.println("Your are now in the house what now?");

这意味着执行System.out.println("Your are now in the house what now?");而不管if语句。

Answer 4

类名应以Java中的大写字母开头：walkthrough - ＆gt; Walkthrough