Question

我正在使用socket io v0.9.16我想更改套接字ID

io.on('connection', function(socket){

      socket.id = 123;
      io.sockets.sockets[123].emit('test'); // emit doesn't work

});

任何想法？我怎么能这样做

Answer 1

您无需更改套接字的ID（事实上，这可能会破坏某些内容）。你想加入一个房间。这应该有效（假设你有一个客户端监听器用于＆＃39; test＆＃39;）：

---
title: "Lord of the Rings"
author: "J. R. R. Tolkien"
header-includes:
  - \usepackage{xcolor}
  - \usepackage{fetamont}
  - \newcommand*\eiadfamily{\fontencoding{OT1}\fontfamily{eiad}\selectfont}
  - \newcommand{\mytitle}{\eiadfamily}
  - \newcommand{\myauthor}{\ffmfamily \textcolor{blue}}
  - \pretitle{\vspace{\droptitle}\centering\huge\eiadfamily}
  - \preauthor{\centering\large\myauthor}
output: pdf_document
---

```{r setup, include=FALSE}
knitr::opts_chunk$set(echo = TRUE)
```


## Chapter 1

Answer 2

SocketIO Docs说

Socket.IO中的每个Socket都由一个随机的，不可思议的唯一标识符Socket＃id
标识。

所以也许你可以这样做。

var socket_list = [];

io.on('connection', function(socket){

  socket_list[""+123] = socket.id;
  io.sockets.sockets[socket_list[""+123]].emit('test');

});

socketio手动设置套接字ID

2 个答案: