Question

我设计了一个带MySQL表的swing接口。当选择第一个组合框值（品牌名称）时，我以两种方式放置两个组合框，第二个组合框值（所选品牌下的可用项目）将通过mysql查询加载。我的代码是......

try{
    String url = "jdbc:mysql://localhost:3306/databasename";
    String login = "root"; String password = ""; Connection con = DriverManager.getConnection(url, login, password);
    try{
        comboBox1 = new JComboBox(); comboBox1.setEditable(false);
        comboBox1.addItem("- - -");
        Statement stmt1=null;
        String query1 = "SELECT brand FROM brands";
        stmt1 = con.createStatement();
        ResultSet rs1 = stmt1.executeQuery(query1);
        while(rs1.next()) {comboBox1.addItem(rs1.getString(1));}
        comboBox2 = new JComboBox(); comboBox2.setEditable(false);
        comboBox1.addActionListener(new ActionListener() {
            public void actionPerformed(ActionEvent event){
                String comboBox1Selected=comboBox1.getSelectedItem().toString();
                try{
                    Statement stmt2=null;
                    String query2 = "SELECT item FROM "+comboBox1Selected+"";
                    stmt2 = con.createStatement();
                    ResultSet rs2 = stmt2.executeQuery(query2);
                    while(rs2.next()) {comboBox2.addItem(rs2.getString(1));}
                }
                catch (SQLException ex1) {JOptionPane.showMessageDialog(null,"Failed to Item-List..!"); ex1.printStackTrace(); return;}
            }
         });
    }
    catch (SQLException ex2) {JOptionPane.showMessageDialog(null,"Failed to Brand-List..!"); ex2.printStackTrace(); return;}
}
catch (SQLException ex3) {ex3.printStackTrace(); JOptionPane.showMessageDialog(null,"Unable to Connect..!"); return;}

问题是，尽管组合框运行正常，但如果我从第一个组合框中选择另一个选项，则第二个组合框不会避免使用较旧的值＆＃34; （它们以较新的值出现）。

可能是什么原因......？任何人都可以解释..？提前谢谢。

Answer 1

在此处comboBox2.removeAllItems()

添加新项目之前，请致电while(rs2.next()) {comboBox2.addItem(rs2.getString(1));}

JComboBox中的MySQL表值

1 个答案: