Question

目前我有两个数据存储在sql db中，然后被拉入我的网站。我想要的是存储的两个数据被分开而不是总计在一起。

所以我设置了我的数据库：

DROP TABLE IF EXISTS totals;
    CREATE TABLE totals (
    id int(11) NOT NULL AUTO_INCREMENT,
    total float NOT NULL,
    PRIMARY KEY (id)
) ;

INSERT INTO totals VALUES (1, 0);

我正在使用的PHP：

$api = array();
$api[] = 'http://api.jo.je/justgiving/data/myuserpage';
$api[] = 'http://api.jo.je/justgiving/data/myuserpage2';

$total = 0;

foreach($api as $data) {

    $open = file_get_contents($data);

    $feed = json_decode($open);

    if(is_object($feed)) {

        $total = $total + $feed->donations_total;

    }

}

// database connection
$conn = new PDO("mysql:host=$dbhost;dbname=$dbname",$dbuser,$dbpass);   // new data
$id = 1;
// query
$sql = "SELECT total 
        from totals
        WHERE id=?";

$q = $conn->prepare($sql);
$q->execute(array($id));

$data = $q->fetch();


$total = $data['total'];

作为一个noobie，我只需要一些帮助来存储两个单独的数据而不是一个。

Answer 1

我认为您只需要在表格中使用两个单独的列：

CREATE TABLE totals (
    id int(11) NOT NULL AUTO_INCREMENT,
    total1 float NOT NULL,
    total2 float NOT NULL,
    PRIMARY KEY (id)
) ;


$api = array(
    'total1' => 'http://api.jo.je/justgiving/data/myuserpage',
    'total2' => 'http://api.jo.je/justgiving/data/myuserpage2',
);

// The saving part is missing from your code, but it should be something like
$sql   = "UPDATE totals SET {$source}=? WHERE id=?";$q = $conn->prepare($sql);
$query = $conn->prepare($sql);
// Note: the above assumes that the "id" already exists. Otherwise
// you need an "UPSERT" (UPdate or inSERT) that will insert a new value or update
// it if it already exists. Find more @ this answer:
// https://stackoverflow.com/questions/15383852/sql-if-exists-update-else-insert-into

/*
* Instead of adding up the two API calls' results, we store them separately
*
* Of course the value of "id" here must be the same as in the second page, or
* what you will retrieve will NOT be what you have stored!
*/
foreach($api as $column => $source) {    
    $data = file_get_contents($source);
    $feed = json_decode($data);
    if (is_object($feed)) {
        $value = $feed->donations_total;
        $query->execute(array($value, $id));
    }
}

现在在第二页

// query
$sql = "SELECT total1, total2 from totals WHERE id=?";
$q = $conn->prepare($sql);
$q->execute(array($id));

$data = $q->fetch();

$total1 = $data['total1'];
$total2 = $data['total2'];

（This是上述答案的链接。）

mySQL将存储在表中的数据分开

1 个答案: