Question

请检查我的代码：

<?php
  $operarors = array( '+', '-', '*' );
  $randOperator = array($operarors[rand(0,2)], $operarors[rand(0,2)]);
  $num1 = rand(0,10);
  $num2 = rand(0,10);
  $num3 = rand(0,10);

  $result = $num1.$randOperator[0].$num2.$randOperator[1].$num3;
  echo "The math: $num1 $randOperator[0] $num2 $randOperator[1] $num3 = $result";
?>

在上面的代码中，我没有得到我的总结果数。

假设我收到3+4*5，输出应为23，但它显示字符串3+4*5。

请帮帮我。

Answer 1

你不能像这样连接运算符。我建议做这样的事情：

<?php
function operate($op1, $operator, $op2) {
    switch ($operator) {
        case "+":
            return $op1 + $op2;
        case "-":
            return $op1 - $op2;
        case "*":
            return $op1 * $op2;
    }
}

$operators = array( '+', '-', '*' );

// performs calculations with correct order of operations
function calculate($str) {
    global $operators;

    // we go through each one in order of precedence
    foreach ($operators as $operator) {
        $operands = explode($operator, $str, 2);
        // if there's only one element in the array, then there wasn't that operator in the string
        if (count($operands) > 1) {
            return operate(calculate($operands[0]), $operator, calculate($operands[1]));
        }
    }

    // there weren't any operators in the string, assume it's a number and return it so it can be operated on
    return $str;
}

$randOperator = array($operators[rand(0,2)], $operators[rand(0,2)]);
$num1 = rand(0,10);
$num2 = rand(0,10);
$num3 = rand(0,10);

$str = "$num1 $randOperator[0] $num2 $randOperator[1] $num3";

echo "$str = ", calculate($str), PHP_EOL;

Answer 2

正如@AndreaFaulds所说，或者使用回调:(虽然使用array_reduce并且所有这些数组指针魔术都没有必要）。

<?php

$ops = [
    '+' => function ($op1, $op2) { return $op1 + $op2; },
    '*' => function ($op1, $op2) { return $op1 * $op2; },
    '-' => function ($op1, $op2) { return $op1 - $op2; }
];

$nums = [rand(0, 10), rand(0, 10), rand(0, 10)];
$operators = [array_rand($ops), array_rand($ops)];

$initial = array_shift($nums);
$result = array_reduce($nums, function ($accumulate, $num) use (&$operators, $ops) {
    return $ops[each($operators)[1]]($accumulate, $num);
}, $initial);

注意，[] short array syntax的版本要求为 PHP 5.4 + 。

Answer 3

你应该使用+运算符而不是。运营商。的。只需将它粘贴在一起，就像值是字符串一样。

PHP数学随机数计算

3 个答案: