Question

我想从谷歌地图版本3到json解析数据。我想获得locaityName，AdministrativeAreaName和状态代码等详细信息。我可以知道如何解析这些数据吗？谢谢

Answer 1

function getGoogleAddressCoordinates()
    {
        //using the google maps api to get the long and lat coordinates of addresss
        //using form post variables
        $address =trim($_POST['address']);
        $city = trim($_POST['city']);
        $state = trim($_POST['state']);

        //formats the address add '+' into space
        $address = str_replace( ' ', '+' ,$address);
        $city = str_replace( ' ', '+', $city);
        $address = preg_replace("[^A-Za-z0-9]", '+', $address ); //remove non alpha numeric chars such as extra spaces.
        $address_str = $address.',+'. $city.',+'.$state;
        $geo_url = "http://maps.google.com/maps/api/geocode/json?address=$address_str&sensor=false";
        //echo $geo_url;
        //echo file_get_contents($geo_url);
        $json_result = json_decode(file_get_contents($geo_url));

        $geo_result =  $json_result->results[0];
        $coordinates = $geo_result->geometry->location;

        //see if the it is locating the real address or just apox location, or in most cases a bad address
        if($geo_result->types[0] == 'street_address')
            $coordinates->valid_address  = TRUE;
        else
            $coordinates->valid_address  = FALSE;

        return $coordinates;
    }

Answer 2

您可以使用json_encode和json_decode函数来解析json数据。

更多信息：

http://php.net/manual/en/function.json-encode.php

Answer 3

PHP有json_decode()将JSON数据流转换为PHP数组或对象。

Answer 4

使用PHP PECL json库

json_decode()

http://php.net/manual/en/function.json-encode.php

只是一个建议，如果函数没有返回任何意味着JSON中存在语法错误的东西，它就不会引发任何错误或记录。

用json和php解析google maps api v3中的数据

4 个答案: