我正在使用DB2。我有这个问题:
SELECT DISTINCT
ORDER_NUMBER,
trdm as TRADEMARK,
cmdnsm as CUSTOMER_NAME
FROM DB1.ORDFA
JOIN DB2.CCADF ON SFORD# = WDRSO
JOIN DB2.DADA06 ON WD3ADF = WD3FLA
JOIN DB1.CMP1 ON C1LK2 = SF2LK
WHERE YEAR = '14' AND PART = '5484'
ORDER BY CUSTOMER_NAME, TRADEMARK
我从上面的查询中得到了这个结果集
order_number trademark customer_name
2220824. AIR EPR PRODUCTS INC
2254614. AVALON EPR PRODUCTS INC
2214146. AVALON EPR PRODUCTS INC
2338002. AVALON EPR PRODUCTS INC
2102733. BOSS EPR PRODUCTS INC
2286148. CDC EPR PRODUCTS INC
2116148. CDC EPR PRODUCTS INC
2032105. HC SUMMLC
2014046. HC SUMMLC
2232312. SDEXO SUMMLC
2267369. SDEXO SUMMLC
2085280. SDEXO SUMMLC
2170433. SDEXO SUMMLC
2179283. SDEXO SUMMLC
2378745. SDEXO SUMMLC
我需要的是一个DB2查询,它会给我这个结果集:
NUM_ORDERS TRADEMARK CUSTOMER_NAME
6 SDEXO SUMMLC
3 AVALON EPR PRODUCTS INC
2 CDC EPR PRODUCTS INC
2 HC SUMMLC
1 BOSS EPR PRODUCTS INC
1 AIR EPR PRODUCTS INC
答案 0 :(得分:4)
如果DB2支持ansi标准sql,我相信您只需要添加count
和group by
:
SELECT
COUNT(DISTINCT ORDER_NUMBER) AS NUM_ORDERS,
trdm as TRADEMARK,
cmdnsm as CUSTOMER_NAME
FROM DB1.ORDFA
JOIN DB2.CCADF ON SFORD# = WDRSO
JOIN DB2.DADA06 ON WD3ADF = WD3FLA
JOIN DB1.CMP1 ON C1LK2 = SF2LK
WHERE YEAR = '14' AND PART = '5484'
GROUP BY trdm, cmdnsm
ORDER BY NUM_ORDERS DESC, CUSTOMER_NAME, TRADEMARK
答案 1 :(得分:2)
尝试这样的事情:
SELECT COUNT(DISTINCT ORDER_NUMBER) AS ORDER_NUMBER,
TRADEMARK,
CUSTOMER_NAME
FROM DB1.ORDFA
JOIN DB2.CCADF ON SFORD# = WDRSO
JOIN DB2.DADA06 ON WD3ADF = WD3FLA
JOIN DB1.CMP1 ON C1LK2 = SF2LK
WHERE YEAR = '14' AND PART = '5484'
GROUP BY CUSTOMER_NAME, TRADEMARK
ORDER BY ORDER_NUMBER DESC