在mysql select query中需要建议。
圈子工作时间：9AM to 6PM
案例1：
If ticket was assigned to circle at 5 pm on Day 1
and was closed by circle at 11 am on Day 2,
then time diff should be 3 hrs.
案例2：
If a ticket is assigned at 7 pm on Day1,
then timediff will only start from 9 am on Day 2
案例3：
If ticket is escalated on a Sunday,
then it's timediff will start from 9 am on Monday
答案 0 :(得分：0)
您可以引入自己的日历，仅计算从某个固定日期开始的工作秒数。 然后，您可以像使用正常时间戳一样进行计算，并获得＆＃34;工作秒数＆＃34;两个时间戳之间。
您需要一层逻辑，将实际日期转换为＆＃34;工作秒数＆＃34;。
您需要决定是否 a）第1天，18：00h =第2天，09：00h 要么 b）第1天，18：00h + 1 =第2天，09：00h
让我们使用a）作为例子：
案例1：
Ticket is assigned at Timestamp = 8 * 60 (8 hours since the start of time)
Ticket is closed at Timestamp = 11 * 60
time diff = 11*60 - 8*60 = 3*60
案例2：
Ticket is assigned at Timestamp = 0 (would have to be convertd before going to db)
Ticket age is current Timestamp
使用每年（/月/日）的表格转换点可以加速转化