我正在处理一项任务,我使用扫描程序读取.txt文件的行和标记。我需要进行一些转换并重新排列一些字符串,这是我使用一些辅助方法完成的。问题是代码只适用于从文件中读取的每一行。我想我可能在代码的开头某处乱搞了一些东西。我需要修改的任何提示或提示?这就是我所拥有的:
public static void main(String[] args) throws FileNotFoundException {
Scanner input = new Scanner(new File("PortlandWeather2013.txt"));
while (input.hasNextLine()) {
String header = input.nextLine();
System.out.println(header);
Scanner input2 = new Scanner(header);
while (input2.hasNextLine()){
String bottomHeader = input.nextLine();
System.out.println(bottomHeader);
String dataLines = input.nextLine();
Scanner linescan = new Scanner(dataLines);
while (linescan.hasNext()){
String station = linescan.next();
System.out.print(station+ " ");
String wrongdate = linescan.next();
String year = wrongdate.substring(0,4) ;
String day = wrongdate.substring(6);
String month = wrongdate.substring(4,6);
System.out.print(month + "/" + day + "/" + year);
double prcp = linescan.nextDouble();
System.out.print("\t "+prcpConvert(prcp));
double snwd = linescan.nextDouble();
System.out.print("\t " + snowConvert(snwd));
double snow = linescan.nextDouble();
System.out.print("\t" + snowConvert(snow));
double tmax = linescan.nextDouble();
System.out.print("\t" + tempConvert(tmax));
double tmin = linescan.nextDouble();
System.out.println("\t" + tempConvert(tmin));
}
}
}
}
public static double prcpConvert(double x){
double MM = x/1000;
double In = MM * 0.039370;
double rounded = Math.round(In * 10)/10;
return rounded;
}
public static double snowConvert(double x){
double In = x * 0.039370;
double rounded = Math.round(In * 10)/10;
return rounded;
}
public static double tempConvert(double x){
double celsius = x/10;
double fahrenheit = (celsius *9/5)+32;
double rounded = Math.round(fahrenheit *10)/10;
return rounded;
}
答案 0 :(得分:0)
nextLine()
并不只是获取最后一行,它也会前进一行。在你的第二个循环之前,你正在调用nextLine()
两次,导致你在循环的每次迭代中前进两行。
您可以通过设置dataLines = bottomHeader
而不是再次调用nextLine()
来解决问题。