Question

我有3个表：list1，vegetables，list2 在pag1.php中，我在“list1”表中插入值，从这里我携带最后插入的id（fruitid）并将其携带到下一个表单page2.php。在这个页面中我有一个复选框形式的项目列表显示在“vegetables”表中，从这里用户可以选择多个值保存在第三个表“list2”中。我想要做的是从第一页到最后一页携带水果ID并将其插入第三个表“list2”。（例如，如果用户从复选框中选择3个值，则这3个值应保存在3行“list2”表中，每行都有fruitid。

表格视图是）我有的 list1表

id   fruit
1    mango
2    apple

蔬菜餐桌

id  vegetables
1    potato
2    Cauliflower

我希望得到什么 list2表

id  vegetableid   fruitid
1   1             2
2   2             2

page1.php中

<?php
    ob_start();
    include('co_session.php');
    $con=mysqli_connect("localhost","root","pwd","root");
    // Check connection
    if (mysqli_connect_errno()) {
      echo "Failed to connect to MySQL: " . mysqli_connect_error();
    }
    if($_POST){
    // escape variables for security
    $fruit = mysqli_real_escape_string($con, $_POST['fruit']);

    $sql="INSERT INTO list1 (fruit) VALUES ('$fruit')";

    if (!mysqli_query($con,$sql)) 
                {
                    die('Error: ' . mysqli_error($con));
                }

    $fruitid= mysqli_insert_id($con); 


    header("Location: page2.php?id=$fruitid ");

            mysqli_close($con);
            }
    ?>
    <form class="form-horizontal" role="form" action="" enctype="multipart/form-data" method="post">
    <div class="col-md-6">
        <div class="form-group">
            <label class="col-lg-4 control-label">Country</label>
                <div class="col-lg-6">
                    <input class="form-control" value="" type="text" name="fruit">
                </div>
        </div>
    </div>

    <div class="col-md-11">
        <div class="form-group">
        <center><input class="btn btn-primary" value="Next " type="submit" name="submit"></center>
        </div>
    </div>
    </form>

第二步提交第一个表单后，它会被重定向到page2.php，在那里获取id。例如url是page2.php？id = 1

<form class="form-horizontal" role="form" action="insert.php?id=<?php echo $_GET['fruitid'];?>" enctype="multipart/form-data" method="post">
<?php
    $servername = "localhost";
    $username = "root";
    $password = "pwd";
    $dbname = "root";

    $con = mysqli_connect($servername, $username, $password, $dbname);
    // Check connection
    if (!$con) {
        die("Connection failed: " . mysqli_connect_error());
        }
        echo "<label class='heading'>Select :</label></br>";

        $sql = "SELECT * FROM vegetables";
        $result = $con->query($sql);
        while($row = $result->fetch_assoc()) {

    echo " <input type='checkbox' name='vegetable[]' value='".$row['id']."'> '<label>' '".$row['vegetable']."' '</label>' <br>";
}
?>
</form>

第三步此表单将重定向到insert.php页面以存储值

insert.php

<?php
ob_start();
include('co_session.php');
$con=mysqli_connect("localhost","root","pwd","root");
// Check connection
if (mysqli_connect_errno()) {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
if(isset($_POST['submit']))
$fruitid = $_GET['fruitid'];
    {
        if(!empty($_POST['vegetable'])) 
            {
                $checked_count = count($_POST['vegetable']);
                foreach($_POST['vegetable'] as $selected) 
                    {
                        //echo "<p>".$selected ."</p>";
                        $sql="INSERT INTO list2 (vegetableid,fruitid) VALUES ('$selected','$fruitid')";
                        if (!mysqli_query($con,$sql)) 
                            {
                                die('Error: ' . mysqli_error($con));
                            }
                    }
            }
        else
            {
                echo "<b>Please Select Atleast One Option.</b>";
            }
    }
?>

问题是，直到第2页的网址我得到了ID，但之后我无法以适当的方式向前推进

Answer 1

page2.php上的表单应具有其操作值action="insert.php?id=<?php echo $_GET['id'];?>"

并在insert.php $fruitid = $_GET['id'];

中

将id从一个表单传递到另一个表单并插入另一个表

1 个答案: