Question

我有这个MySQL表：

+------------+-------+---------------+
| date       | event | name          |
+------------+-------+---------------+
| 2014-08-22 |     3 | A             |
| 2014-08-22 |     3 | B             |
| 2014-08-26 |    11 | A             |
| 2014-08-26 |    15 | B             |
| 2014-08-27 |     1 | A             |
| 2014-08-27 |     1 | B             |
| 2014-09-10 |     2 | A             |
| 2014-09-10 |     2 | B             |
+------------+-------+---------------+

我想显示如下所示的上述数据：

+------------+-------+---------------+
| date       | A     | B             |
+------------+-------+---------------+
| 2014-08-22 |     3 | 3             |
| 2014-08-26 |    11 | 15            |
| 2014-08-27 |     1 | 1             |
| 2014-09-10 |     2 | 2             |
+------------+-------+---------------+

请帮助我如何获得格式

Answer 1

好的，我创建了你的表并将其称为tester：

mysql> select * from tester;
+------------+-------+------+
| date       | event | name |
+------------+-------+------+
| 2014-08-22 |     3 | A    |
| 2014-08-22 |     3 | B    |
| 2014-08-26 |    11 | A    |
| 2014-08-26 |    15 | B    |
| 2014-08-27 |     1 | A    |
| 2014-08-27 |     1 | B    |
| 2014-09-10 |     2 | A    |
| 2014-09-10 |     2 | B    |
+------------+-------+------+
8 rows in set (0.00 sec)

我的想法很简单：

我创建了一个视图，其中只保存A值及其对应的日期。
我创建了第二个视图，其中只保存B值及其对应的日期
我在他们的约会时加入了这些观点。

以下是他们演示的完整步骤：

mysql> create view theAs as (select date, event AS A from tester where name='A'); 
Query OK, 0 rows affected (0.30 sec)

mysql> select * from theAs;
+------------+------+
| date       | A    |
+------------+------+
| 2014-08-22 |    3 |
| 2014-08-26 |   11 |
| 2014-08-27 |    1 |
| 2014-09-10 |    2 |
+------------+------+
4 rows in set (0.00 sec)

mysql> create view theBs as (select date, event AS B from tester where name='B'); 
Query OK, 0 rows affected (0.30 sec)

mysql> select * from theBs;
+------------+------+
| date       | B    |
+------------+------+
| 2014-08-22 |    3 |
| 2014-08-26 |   15 |
| 2014-08-27 |    1 |
| 2014-09-10 |    2 |
+------------+------+
4 rows in set (0.00 sec)

mysql> select theAs.date, theAs.A, theBs.B from theAs join theBs on theAs.date=theBs.date;
+------------+------+------+
| date       | A    | B    |
+------------+------+------+
| 2014-08-22 |    3 |    3 |
| 2014-08-26 |   11 |   15 |
| 2014-08-27 |    1 |    1 |
| 2014-09-10 |    2 |    2 |
+------------+------+------+
4 rows in set (0.00 sec)

Begueradj

使用mysql php将多维数组行显示为列日期

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