Question

我相信这会有效，但它会在代码的最后一行给我一个错误信息，因为语法无效，我不确定为什么要寻求帮助。

password=123

ask=raw_input("What is the password")

try:

    while ask=="123":
        age=int(raw_input("What is your age"))
        if age >= 18: 
            print("You are able to vote in the United States!")
        else:
            print("You are not able to vote in the United States.")

Answer 1

以下是经过一些细微更改后的代码的工作版本：

password = "123"
ask = raw_input("What is the password?\n")

if ask == password:
    age = int(raw_input("What is your age?\n"))
    if age >= 18: 
        print("You are able to vote in the United States!")
    else:
        print("You are not able to vote in the United States.")

Answer 2

问题是try语句总是需要except子句在语法上有效。

在您的情况下，try语句没有意义（与程序的其他部分一样），因此您应该删除它并相应地突出while块。

可以防止非整数输入，但如果这是你的意图，你应该把它放在那个位置：

password = "123"
ask = raw_input("What is the password")
if ask == password:
    while True:
        try:
            age = int(raw_input("What is your age? "))
            break
        except ValueError:
            print "Please enter an integer number!"

    if age >= 18: 
        print("You are able to vote in the United States!")
    else:
        print("You are not able to vote in the United States.")

我正在尝试创建一个程序，询问您的年龄和Python中的密码

2 个答案: