我希望仅在选中相关复选框时启用单选按钮。所以我需要帮助编写一个通用的javascript代码,它将适用于所有复选框。我有大约100个复选框,因此我不想在javascript代码中手动编写每个ID或名称。是否可以以通用方式呈现代码示例。
<form name=registration>
<table border=1>
<tr>
<td><input type='checkbox' id='c1' name=selcourse value='2-PM-030' onChange="enabledSDF(1,this.value);"> Microsoft Project 2013 </td>
<td> </td><td><input type=radio id=cd name='2-PM-030' value='Dec 11-12'>Dec 11-12</td>
<td><input type=radio id=c1d1 name='2-PM-030' value='Jan 26-27'>Jan 26-27</td><td> </td>
<td> </td><td> </td>
</tr>
<tr>
<td><input type='checkbox' id='c2' name=selcourse value='2-PM-050'> Microsoft Project 2010 </td>
<td><input type=radio id=c2d1 name='2-PM-050' value='Nov 24-25'>Nov 24-25</td>
<td><input type=radio id=c2d2 name='2-PM-050' value='Dec 18-19'>Dec 18-19</td>
<td><input type=radio id=c2d3 name='2-PM-050' value='Jan 29-30'>Jan 29-30</td>
<td> </td><td> </td><td> </td>
</tr>
</table>
</form>
我发现了以下代码,但我不确定如何使其成为通用代码。
<script type="text/javascript">
$(window).load(function(){
$(document).ready(function()
function enabledSDF(i,value){
var form = document.registration;
if(document.getElementById('course_type').value=='C')
{
if (value=="Singaporean"){
document.getElementById("sdf"+i+"0").disabled='';
document.getElementById("sdf"+i+"1").disabled='';
}
else{
document.getElementById("sdf"+i+"0").disabled='disabled';
document.getElementById("sdf"+i+"1").disabled='disabled';
}
}
}
$(document).ready(function()
{
$("#email_acc").click(function()
{
if ( $(this).is(":checked") )
{
$("input[name='radio_email']").removeAttr("disabled");
}else {
$("input[name='radio_email']").attr ( "disabled" , true );
}
});
$("#sys_acc").click(function()
{
if ( $(this).is(":checked") )
{
$("input[name='radio_system']").removeAttr("disabled");
} else {
$("input[name='radio_system']").attr ( "disabled" , true );
}
});
});
</script>
答案 0 :(得分:1)
尝试以下方法:
$(function() {
$('input[type="checkbox"]')
.on('change', checkboxChange) // do it when you change the checkbox
.each(checkboxChange); // as well as once when the page loads
function checkboxChange() {
var $checkbox = $(this);
$('input[name="' + $checkbox.attr('value') + '"]').prop('disabled', !$checkbox.prop('checked'));
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form name=registration>
<table border=1>
<tr>
<td>
<input type='checkbox' id='c1' name=selcourse value='2-PM-030' onChange="enabledSDF(1,this.value);">Microsoft Project 2013</td>
<td> </td>
<td>
<input type=radio id=cd name='2-PM-030' value='Dec 11-12'>Dec 11-12</td>
<td>
<input type=radio id=c1d1 name='2-PM-030' value='Jan 26-27'>Jan 26-27</td>
<td> </td>
<td> </td>
<td> </td>
</tr>
<tr>
<td>
<input type='checkbox' id='c2' name=selcourse value='2-PM-050'>Microsoft Project 2010</td>
<td>
<input type=radio id=c2d1 name='2-PM-050' value='Nov 24-25'>Nov 24-25</td>
<td>
<input type=radio id=c2d2 name='2-PM-050' value='Dec 18-19'>Dec 18-19</td>
<td>
<input type=radio id=c2d3 name='2-PM-050' value='Jan 29-30'>Jan 29-30</td>
<td> </td>
<td> </td>
<td> </td>
</tr>
</table>
</form>
如果单选按钮的名称与禁用它们的复选框的值不同,则需要从已更改为包含它们的<tr>
的复选框进行遍历,然后在其中找到单选按钮。
为此,只需更改我的checkboxChange()
功能,如下所示。
function checkboxChange() {
var $checkbox = $(this);
$checkbox.closest('tr').find('input[type=radio]').prop('disabled', !$checkbox.prop('checked'));
}
答案 1 :(得分:0)
HTML:
<form name=registration>
<table border=1>
<tr>
<td><input type='checkbox' class="des" data-year='2013' name=selcourse value='2-PM-030'> Microsoft Project 2013 </td>
<td> </td><td><input type=radio class="2013" name='2-PM-030' value='Dec 11-12'>Dec 11-12</td>
<td><input type=radio class="2013" name='2-PM-030' value='Jan 26-27'>Jan 26-27</td><td> </td>
<td> </td><td> </td>
</tr>
<tr>
<td><input type='checkbox' class="des" data-year='2010' name=selcourse value='2-PM-050'> Microsoft Project 2010 </td>
<td><input type=radio class="2010" name='2-PM-050' value='Nov 24-25'>Nov 24-25</td>
<td><input type=radio class="2010" name='2-PM-050' value='Dec 18-19'>Dec 18-19</td>
<td><input type=radio class="2010" name='2-PM-050' value='Jan 29-30'>Jan 29-30</td>
<td> </td><td> </td><td> </td>
</tr>
</table>
</form>
的javascript:
$('.des').on('change', function () {
var type = $(this).data('year');
if(this.checked){
$('.' + type).attr('disabled', 'true');
} else {
$('.' + type).removeAttr( "disabled" );
}
});
如果你已经在使用jquery,那么如果你利用那个
会更好