将php mcrypt_encrypt MCRYPT_3DES转换为Java

Question

我有PHP代码

$res = strtoupper(bin2hex(mcrypt_encrypt(MCRYPT_3DES, $this->hex2str($key), $this->hex2str($data), MCRYPT_MODE_ECB)));

public function hex2str($data) { 
      $len = strlen($data); 
      $res = pack("H" . $len, $data);
      return $res; 
} 

我尝试在java版本中创建。
Java代码：

private String doEncrypt3DES(String key, String data) throws Exception{
        SecretKey secretKey;
        byte[] keyValue;
        Cipher c;

        keyValue = Hex.decodeHex(key.toCharArray());
        DESedeKeySpec keySpec = new DESedeKeySpec(keyValue);
        secretKey = SecretKeyFactory.getInstance("DESede").generateSecret(keySpec);

        // Create the cipher
        c = Cipher.getInstance("DESede/ECB/NoPadding");

        c.init(Cipher.ENCRYPT_MODE, secretKey);
        byte[] text = data.getBytes("utf-8"); // Base64.decodeBase64(data);
        byte[] textEncrypt = c.doFinal(text);
        String hex = bytesToHex(textEncrypt);
        return hex;
}

但是他们得到了不同的结果。你能帮我修一下java代码吗？
数据：CED0CF172E8AC451B39FC746C5339F29

密钥：436C6561724B657944657632536E724D436C6561724B6579

Answer 1

对数据使用十六进制解码而不是utf-8解码。