分页,LIMIT不起作用。 PHP /库MySQLi

时间:2014-11-14 02:39:44

标签: php database mysqli pagination limit

这是我的代码:

<?php
$sqlPages = 'SELECT COUNT(id) FROM newsvid WHERE approved=1';
$queryPages = mysqli_query($con, $sqlPages);
$row = mysqli_fetch_row($queryPages);
// Here we have the total row count
$rows = $row[0];
// This is the number of results we want displayed per page
$page_rows = 1;
// This tells us the page number of our last page
$last = ceil($rows/$page_rows);
// This makes sure $last cannot be less than 1
if($last < 1){
    $last = 1;
}
// Establish the $pagenum variable
$pagenum = 1;
// Get pagenum from URL vars if it is present, else it is = 1
if(isset($_GET['pn'])){
    $pagenum = preg_replace('#[^0-9]#', '', $_GET['pn']);
}
// This makes sure the page number isn't below 1, or more than our $last page
if ($pagenum < 1) { 
    $pagenum = 1; 
} else if ($pagenum > $last) { 
    $pagenum = $last; 
}
// This sets the range of rows to query for the chosen $pagenum
$limit = 'LIMIT ' .($pagenum - 1) * $page_rows .',' .$page_rows;
// This is your query again, it is for grabbing just one page worth of rows by applying $limit

$queryMain ="SELECT newsvid.id, newsvid.addName, newsvid.vidTitle, newsvid.vidType, newsvid.size, newsvid.url, newsvid.vidSD, newsvid.published, videoinformation.vidLD, videoinformation.vidYear, videoinformation.vidCity, videoinformation.vidZanr, videoinformation.vidZanr2, videoinformation.vidZanr3, videoinformation.vidQuality, videoinformation.vidTranslated, videoinformation.vidTime  FROM newsvid, videoinformation WHERE newsvid.id = videoinformation.id AND approved=1 ORDER BY DESC $limit";

$resultDisplay = mysqli_query($con, $queryMain);
// This shows the user what page they are on, and the total number of pages
$pagesTitle = "On website <b>$rows</b>";
$pagesOutOf = "Page <b>$pagenum</b> of <b>$last</b>";
// Establish the $paginationCtrls variable
$paginationCtrls = '';
// If there is more than 1 page worth of results
if($last != 1){
    /* First we check if we are on page one. If we are then we don't need a link to 
       the previous page or the first page so we do nothing. If we aren't then we
       generate links to the first page, and to the previous page. */
    if ($pagenum > 1) {
        $previous = $pagenum - 1;
        $paginationCtrls .= '<a href="'.$_SERVER['PHP_SELF'].'?pn='.$previous.'">Previous</a> &nbsp; &nbsp; ';
        // Render clickable number links that should appear on the left of the target page number
        for($i = $pagenum-4; $i < $pagenum; $i++){
            if($i > 0){
                $paginationCtrls .= '<a href="'.$_SERVER['PHP_SELF'].'?pn='.$i.'">'.$i.'</a> &nbsp; ';
            }
        }
    }
    // Render the target page number, but without it being a link
    $paginationCtrls .= ''.$pagenum.' &nbsp; ';
    // Render clickable number links that should appear on the right of the target page number
    for($i = $pagenum+1; $i <= $last; $i++){
        $paginationCtrls .= '<a href="'.$_SERVER['PHP_SELF'].'?pn='.$i.'">'.$i.'</a> &nbsp; ';
        if($i >= $pagenum+4){
            break;
        }
    }
    // This does the same as above, only checking if we are on the last page, and then generating the "Next"
    if ($pagenum != $last) {
        $next = $pagenum + 1;
        $paginationCtrls .= ' &nbsp; &nbsp; <a href="'.$_SERVER['PHP_SELF'].'?pn='.$next.'">Next</a> ';
    }
}
$list = "";

while($row = mysqli_fetch_array($resultDisplay, MYSQLI_ASSOC)){

$list .= "<div class=\"panel-heading\">
<div><a class=\"panel-title btn-block\" href=\"details.php?id=".$row['id']."\"><h3>".$row['id']." | ".$row['vidTitle']."</h3></a></div>
</div>

<div class=\"panel-body\">
<div class=\"imgCover\"><img class=\"imageCover\"src=\"" . $row['url'] . "\"></div>
<div class=\"vidSD\">" . $row['vidSD'] . "</div>
<div class=\"vidDetails\"> 

<hr class=\"style-two\">
<table>
<tr><td class=\"vidDetailsTD\"><strong>" . $lang['vtYear'] . "</strong></td><td class=\"vidDetailsTD\">" . $row['vidYear'] ."</td></tr>
<tr><td class=\"vidDetailsTD\"><strong>" . $lang['vtCity'] . "</strong></td><td class=\"vidDetailsTD\">". $row['vidCity'] ."</td></tr>
<tr><td class=\"vidDetailsTD\"><strong>" . $lang['vtGenre'] . "</strong></td><td class=\"vidDetailsTD\">". $row['vidZanr'] ." , ". $row['vidZanr2'] ." , ". $row['vidZanr3'] . "</td></tr>
<tr><td class=\"vidDetailsTD\"><strong>" . $lang['vtQuality'] . "</strong></td><td class=\"vidDetailsTD\">". $row['vidQuality'] ."</td></tr>
<tr><td class=\"vidDetailsTD\"><strong>" . $lang['vtTranslatedBy'] . "</strong></td><td class=\"vidDetailsTD\">". $row['vidTranslated'] ."</td></tr>
<tr><td class=\"vidDetailsTD\"><strong>" . $lang['vtVideoTime'] . "</strong></td><td class=\"vidDetailsTD\">". $row['vidTime'] .  "</td></tr>
</table> 
</div></div>

<div class=\"panel-footer\">
<h6><strong>" . $lang['vsdAuthor'] . "</strong><a href=\"../userPages/user.php?u=".$row['addName']."\">".$row['addName']."</a></h6>
<div><h6><strong>" . $lang['vsdPublished'] . "</strong>" . $row['published'] . "</h6></div>
</div>";
}




include_once 'inc/sortOrder.php';
mysqli_close($con);


?>

问题是一切正常而不是每页显示1的结果,它会显示所有内容。

当我按下不同的页面时(我的意思是页面更改(视觉上),以及我在哪个页面上也会发生变化。但是列表显示所有结果。

P.S。代码示例不是我的,我只是改编它。我认为 LIMIT 的问题,但代码看起来适合我。

$queryMain ="SELECT newsvid.id, newsvid.addName, newsvid.vidTitle, newsvid.vidType, newsvid.size, newsvid.url, newsvid.vidSD, newsvid.published, videoinformation.vidLD, videoinformation.vidYear, videoinformation.vidCity, videoinformation.vidZanr, videoinformation.vidZanr2, videoinformation.vidZanr3, videoinformation.vidQuality, videoinformation.vidTranslated, videoinformation.vidTime  FROM newsvid, videoinformation WHERE newsvid.id = videoinformation.id AND approved='1'";

我如何添加限制???像queryOne = QueryMain + $limit; ???

0 个答案:

没有答案