while($row=mysql_fetch_array($result))
{
$output .= "<Reports>";
$output .= "<ProjectName>";
$output .= $row['ProjectName'];
$output .= "</ProjectName>";
$output .= "<ProjectCount>";
$output .= $row=mysql_fetch_array($result)
$output .= "</ProjectCount>";
$output .= "</Reports>";
}
我的SQL查询。
SELECT designation.desg_Name AS PM, project.ProjectName,
Case ProjectPhase.PhaseID WHEN 1 THEN 'ScopeofWork' END AS ScopeofWork,
Case ProjectPhase.PhaseID WHEN 2 THEN 'DesignDocument' END AS DesignDocument,
Case ProjectPhase.PhaseID WHEN 3 THEN 'Storyboard' END AS Storyboard,
Case ProjectPhase.PhaseID WHEN 4 THEN 'Alpha' END AS Alpha,
Case ProjectPhase.PhaseID WHEN 5 THEN 'Beta' END AS Beta,
Case ProjectPhase.PhaseID WHEN 6 THEN 'Gold' END AS Gold,
Case ProjectPhase.PhaseID WHEN 7 THEN 'TE Storyboard review' END AS 'TE Storyboard review'
FROM `tycodashboard` t JOIN project ON project.projectID = t.projectID
JOIN projectPhase ON projectPhase.PhaseID = t.PhaseID
JOIN designation ON designation.designationID = t.designationID
我可以像这样返回表中的行数,我收到XML标记错误。
答案 0 :(得分:1)
$output .= $row=mysql_fetch_array($result)
会输出Array
,也许您想要$output .= mysql_num_rows($result);
?
答案 1 :(得分:0)
你可以在php
中使用函数 count($ array)