Question

把我的大脑放在这个上面。我有一个字符串，例如MON-123ABC / 456 78＃AbCd

我想要的是一个数组或列表如下

[0] = MON
[1] = -
[2] = 123
[3] = ABC
[4] = /
[5] = 456
[6] =  ' '  (space character that is between 6 and 7 in the example string)
[7] = 78
[8] = #
[9] = A
[10] = b
[11] = C
[12] = d

当从一种类型的字符（字母，数字，非字母/数字，大写到小写）转换到另一种字符时，我基本上想要分割任何字符串输入

RegExp或C＃代码都可以。我有一个简单的正则表达式0+ |（？＆lt; =（[1-9]））（？= [1-9]）（？！\ 1）但这只是在数字上分开，我的正则表达式不是那个好。我已经使用了一些C＃代码来循环使用字符串，但我对字符类型之间的转换有问题。

示例2：另一示例输入字符串可以是123qaz ZBC / 45678＃Ab-Cd

它在每次过渡时都在吐痰而不是关键的位置。在示例2中，顺便提一下z和Z之间有两个空格。正如我所提到的那样，类型之间的转换是关键。

Answer 1

有点uggly，分裂在这个正则表达式上：

(?<=[a-z])(?=[^a-z])|(?<=[A-Z])(?=[^A-Z])|(?<=[0-9])(?=[^0-9])|(?<=[a-zA-Z0-9])(?=[^a-zA-Z0-9])|(?<=[^a-z])(?=[a-z])|(?<=[^A-Z])(?=[A-Z])|(?<=[^0-9])(?=[0-9])|(?<=[^a-zA-Z0-9])(?=[a-zA-Z0-9])

<强>详细信息：

(?<=[a-z])(?=[^a-z])                : split between lc alpha and not alpha
|(?<=[A-Z])(?=[^A-Z])               : or split between UC alpha and not alpha
|(?<=[0-9])(?=[^0-9])               : or split between digit and not digit
|(?<=[a-zA-Z0-9])(?=[^a-zA-Z0-9])   : or split between alphanum and not alphanum
|(?<=[^a-z])(?=[a-z])               : reverse of above
|(?<=[^A-Z])(?=[A-Z])
|(?<=[^0-9])(?=[0-9])
|(?<=[^a-zA-Z0-9])(?=[a-zA-Z0-9])

它给了我：

("MON", "-", 123, "ABC", "/", 456, " ", 78, "#", "A", "b", "C", "d")

Answer 2

([A-Z]+|[a-z]+|\d+|[^\da-zA-Z]+)

怎么样？

int i = 0;
foreach(Match match in Regex.Matches(@"MON-123ABC/456 78#AbCd", @"([A-Z]+|[a-z]+|\d+|[^\da-zA-Z]+)"))
{
    if (match.Success)
    {
        Console.WriteLine("{0}\t{1}", ++i, match.Groups[0]);
    }
}

有关

1       MON
2       -
3       123
4       ABC
5       /
6       456
7
8       78
9       #
10      A
11      b
12      C
13      d

Answer 3

这是一个不使用正则表达式的解决方案。

public static IEnumerable<string> SplitOnType(string str)
{
    StringBuilder builder = new StringBuilder();
    int previousType = -1;
    foreach (char c in str)
    {
        int type;
        if ('a' <= c && c <= 'z')
            type = 0;
        else if ('A' <= c && c <= 'Z')
            type = 1;
        else if ('0' <= c && c <= '9')
            type = 2;
        else
            type = 3;

        if (previousType != -1 && type != previousType)
        {
            yield return builder.ToString();
            builder.Clear();
        }

        builder.Append(c);
        previousType = type;
    }

    if (builder.Length > 0)
        yield return builder.ToString();
}

请注意，这会根据描述将所有非字母数字字符组合在一起，但只需添加其他else if子句即可更改为进行任何添加分组。

Answer 4

(?=-|\/|\s|#)|(?<=-|\/|\s|#)|(?!\d)(?=\d)|(?<=\d)(?=[^\d])|(?<=[a-z])|(?=[a-z])

试试这个。参见demo。替换\n

http://regex101.com/r/tF5fT5/55

当字符串中的字符发生更改时，RegEx split / tokenize string

4 个答案: