Question

你将自动播放着名的歌曲“99瓶墙上的XXX”。您将打印歌曲的所有99节经文的歌词。 使用循环！如果你不知道歌词，用谷歌查一下。

该计划应该：

询问用户的年龄
如果用户年满21岁或以上，请询问他们是否喜欢啤酒或苏打水

一个。如果他们不满21岁或他们更喜欢苏打水，那么歌词是“99 墙上的苏打水瓶“

湾如果它们超过21，则它是“99瓶啤酒”

你必须使用WHILE LOOP并且计数器变量必须是打印声明！

所以第一节将是：

墙上有99瓶苏打水

如果其中一个瓶子从墙上掉下来

......墙上的.98瓶苏打水

最后一节：

墙上的一瓶苏打水

1瓶苏打水

如果那瓶单独的汽水应该从墙上掉下来

墙上没有苏打水瓶！

所以想想，你需要添加什么来循环打印最后一节经文歌词略有不同？

//这是我的代码。当我运行它时，最后的歌词显示如下

1 of beer on the wall
 1 bottles of beer
 If one of those bottles should fall off the wall
 ...0 bottles of beer on the wall
 0 of beer on the wall
 0 bottles of beer
 If that lone bottle of beer should fall off the wall
 No bottles of beer on the wall

//怎么做＆＃34; 0＆＃34;瓶子部分不显示??

Scanner user = new Scanner(System.in);

           int age, beverage;


           System.out.println("Please type in your age");
           age = user.nextInt();

           user.nextLine();
           System.out.println("Would you like soda or beer? soda=1 beer=2");
           beverage = user.nextInt();

        if(age<21 || beverage==1)
           {
           int bottles = 99;
            while( 1<= bottles){
                System.out.println(bottles+" of soda on the wall");
                System.out.println(bottles+" bottles of soda");
                System.out.println("If one of those bottles should fall off the wall");
                bottles--;
                System.out.println("..."+bottles+" bottles of soda on the wall");
            if(bottles==0){
                System.out.println(bottles+" of soda on the wall");
                System.out.println(bottles+" bottles of soda");
                System.out.println("If that lone bottle of soda should fall off the wall");
                System.out.println("No bottles of soda on the wall");
            }
        }
    }
        if(age>=21 && beverage == 2)
        {
            int bottles=99;
            while(1<= bottles){
                System.out.println(bottles+" of beer on the wall");
                System.out.println(bottles+" bottles of beer");
                System.out.println("If one of those bottles should fall off the wall");
                bottles--;
                System.out.println("..."+bottles+" bottles of beer on the wall");
            if(bottles==0){
                System.out.println(bottles+" of beer on the wall");
                System.out.println(bottles+" bottles of beer");
                System.out.println("If that lone bottle of beer should fall off the wall");
                System.out.println("No bottles of beer on the wall");
            }
        }
    }

        }
    }

Answer 1

我相信你的循环测试条件已经逆转了。另外，我会使用Formatter syntax使用printf来实现此功能。然后您可以以格式包含饮料。如果我像运行它一样运行它

public static void main(String[] args) {
    Scanner user = new Scanner(System.in);
    int bottles = 99;

    System.out.println("Please type in your age");
    int age = user.nextInt();
    System.out.println("Would you like soda or beer? soda=1 beer=2");
    int beverage = user.nextInt();
    String drink = (age >= 21 && beverage == 2) ? "beer" : "soda";
    while (bottles > 1) { //  <-- swap 1 and bottles.
        System.out.printf("%d bottles of %s on the wall%n", bottles, drink);
        System.out.printf("%d bottles of %s%n", bottles, drink);
        System.out.println("If one of those bottles "
                + "should fall off the wall");
        bottles--;
        System.out.printf("... %d bottles of %s on the wall.%n", bottles,
                drink);
    }
    System.out.printf("%d bottle of %s on the wall%n", 1, drink);
    System.out.printf("%d bottle of %s%n", 1, drink);
    System.out.printf("If that lone bottle of %s should fall off the wall%n",
                drink);
    System.out.printf("No bottles of %s on the wall!%n", drink);
}

Answer 2

 if(age>=21 && beverage==2)
       int bottles = 99; /* initialize bottles here*/

为什么运行程序时数字不正确显示？

2 个答案: