Question

我试图用C ++实现某种二进制补码算法，到目前为止我认为我的逻辑是正确的。但是，当我运行invalid types 'int[int]' for array subscript

时，我收到以下错误

#include <iostream>
#include <stdio.h>
using namespace std;

int main(){

    int a[4] = {0, 2, 3, 5};
    int b[4] = {9, 7, 8 ,4};

    int sum = 0;
    int transmit = 0;
    int c{0};

    for (int k=3;k>0;k--){
        sum = a[k]+b[k]+transmit;
        c[k+1]=sum%10;
        transmit=sum/10;
    }

    c[0] = transmit;
    return 0;
}

Answer 1

c的类型为int

int c{0};

你试图取消引用它，好像它是一个数组：

c[k+1]=sum%10;

您无法合法取消引用int。

Answer 2

我猜你的目的是做两个int数组的加操作？一个小解释：你必须为'c'声明五个单位，因为可能有一个额外的载体（你称为传输）

#include <iostream>
#include <stdio.h>
using namespace std;

int main(){

    int a[4] = {0, 2, 3, 5};
    int b[4] = {9, 7, 8 ,4};

    int sum = 0;
    int transmit = 0;
    int c[5] = {0};

    for (int k=3;k>0;k--){
        sum = a[k]+b[k]+transmit;
        c[k+1]=sum%10;
        transmit=sum/10;
    }

    c[0] = transmit;
    return 0;
}

使用这种格式：十进制整数数组，它们有点难以直接转换为二进制。但我仍然可以尝试提出解决方案：

// first convert to an unsigned int
unsigned int result = 0;
for (int k = 0; k < 5; ++k) {
    result *= 10;
    result += c[k];
}

// then convert to binary
char binary[32]; // 32bit should be enough
int len = 0;
while (result > 0) {
    binary[len++] = (result % 2) + '0';
    result /= 2;
}

// finally print binary
for (int k = len - 1; k >= 0; --k) {
    printf("%c", binary[k]);
}

完整的计划：

#include <iostream>
#include <stdio.h>
using namespace std;

int main(){

    int a[4] = {0, 2, 3, 5};
    int b[4] = {9, 7, 8 ,4};

    int sum = 0;
    int transmit = 0;
    int c[5] = {0};

    for (int k=3;k>0;k--){
        sum = a[k]+b[k]+transmit;
        c[k+1]=sum%10;
        transmit=sum/10;
    }

    c[0] = transmit;

    // first convert to an unsigned int
    unsigned int result = 0;
    for (int k = 0; k < 5; ++k) {
        result *= 10;
        result += c[k];
    }

    // then convert to binary
    char binary[32]; // 32bit should be enough
    int len = 0;
    while (result > 0) {
        binary[len++] = (result % 2) + '0';
        result /= 2;
    }

    // finally print binary
    for (int k = len - 1; k >= 0; --k) {
        printf("%c", binary[k]);
    }

    printf("\n");

    return 0;
}

C ++中的二进制补码 - 数组下标的无效类型'int [int]'

2 个答案: