我想在C中打印一个可变小数位数的数字。 我写了代码
#include<stdio.h>
main()
{ int a;
printf("Upto which number of decimal places you want to print value of '2.554648' ?");
scanf("%d", &a);
printf("Value of '2.554648 upto %d number of decimal places = %.af", a, 2.554648);
return 0;
}
答案 0 :(得分:6)
使用printf()
中的*
标记您想要的小数位数:
#include <stdio.h>
int main(void)
{
int a;
printf("Upto which number of decimal places you want to print value of '2.554648' ?");
scanf("%d", &a);
printf("Value of '2.554648 upto %d number of decimal places = %.*f", a, a, 2.554648);
return 0;
}
答案 1 :(得分:3)
您需要*
格式说明符。这是一个简短的例子(参见ideone):
#include <stdio.h>
int main(void) {
int a = 5;
double temp = 5.0 / 7;
printf("%.*f",a, temp);
return 0;
}