Question

我对 Swift 中的时间转换有一个（有点？）基本问题。

我有一个整数，我想转换成小时/分钟/秒。

示例： Int = 27005会给我：

7 Hours  30 Minutes 5 Seconds

我知道如何在PHP中执行此操作，但唉，swift不是PHP： - ）

关于我如何在swift中实现这一目标的任何提示都会非常棒！提前谢谢！

Answer 1

定义

func secondsToHoursMinutesSeconds (seconds : Int) -> (Int, Int, Int) {
  return (seconds / 3600, (seconds % 3600) / 60, (seconds % 3600) % 60)
}

使用

> secondsToHoursMinutesSeconds(27005)
(7,30,5)

或

let (h,m,s) = secondsToHoursMinutesSeconds(27005)

上面的函数使用Swift元组一次返回三个值。您可以使用let (var, ...)语法对元组进行解构，也可以根据需要访问单个元组成员。

如果您确实需要使用Hours等单词打印出来，请使用以下内容：

func printSecondsToHoursMinutesSeconds (seconds:Int) -> () {
  let (h, m, s) = secondsToHoursMinutesSeconds (seconds)
  print ("\(h) Hours, \(m) Minutes, \(s) Seconds")
}

请注意，secondsToHoursMinutesSeconds()的上述实现适用于Int个参数。如果您需要Double版本，则需要确定返回值的范围 - 可以是(Int, Int, Double)，也可以是(Double, Double, Double)。你可以尝试类似的东西：

func secondsToHoursMinutesSeconds (seconds : Double) -> (Double, Double, Double) {
  let (hr,  minf) = modf (seconds / 3600)
  let (min, secf) = modf (60 * minf)
  return (hr, min, 60 * secf)
}

Answer 2

在macOS 10.10+ / iOS 8.0+中引入(NS)DateComponentsFormatter来创建可读字符串。

它考虑用户的语言环境和语言。

let interval = 27005

let formatter = DateComponentsFormatter()
formatter.allowedUnits = [.hour, .minute, .second]
formatter.unitsStyle = .full

let formattedString = formatter.string(from: TimeInterval(interval))!
print(formattedString)

可用的单位样式为positional，abbreviated，short，full，spellOut和brief。

有关详细信息，请阅读documenation。

Answer 3

我已经构建了现有答案的mashup，以简化所有内容并减少 Swift 3 所需的代码量。

func hmsFrom(seconds: Int, completion: @escaping (_ hours: Int, _ minutes: Int, _ seconds: Int)->()) {

        completion(seconds / 3600, (seconds % 3600) / 60, (seconds % 3600) % 60)

}

func getStringFrom(seconds: Int) -> String {

    return seconds < 10 ? "0\(seconds)" : "\(seconds)"
}

用法：

var seconds: Int = 100

hmsFrom(seconds: seconds) { hours, minutes, seconds in

    let hours = getStringFrom(seconds: hours)
    let minutes = getStringFrom(seconds: minutes)
    let seconds = getStringFrom(seconds: seconds)

    print("\(hours):\(minutes):\(seconds)")                
}

打印：

00:01:40

Answer 4

在Vadian's answer的基础上，我编写了一个扩展程序，其中Double（其中TimeInterval是一个类型别名）并吐出一个格式化为时间的字符串。

extension Double {
  func asString(style: DateComponentsFormatter.UnitsStyle) -> String {
    let formatter = DateComponentsFormatter()
    formatter.allowedUnits = [.hour, .minute, .second, .nanosecond]
    formatter.unitsStyle = style
    guard let formattedString = formatter.string(from: self) else { return "" }
    return formattedString
  }
}

以下是各种DateComponentsFormatter.UnitsStyle选项的外观：

10000.asString(style: .positional)  // 2:46:40
10000.asString(style: .abbreviated) // 2h 46m 40s
10000.asString(style: .short)       // 2 hr, 46 min, 40 sec
10000.asString(style: .full)        // 2 hours, 46 minutes, 40 seconds
10000.asString(style: .spellOut)    // two hours, forty-six minutes, forty seconds
10000.asString(style: .brief)       // 2hr 46min 40sec

Answer 5

这是一种更有条理/更灵活的方法:( Swift 3）

struct StopWatch {

    var totalSeconds: Int

    var years: Int {
        return totalSeconds / 31536000
    }

    var days: Int {
        return (totalSeconds % 31536000) / 86400
    }

    var hours: Int {
        return (totalSeconds % 86400) / 3600
    }

    var minutes: Int {
        return (totalSeconds % 3600) / 60
    }

    var seconds: Int {
        return totalSeconds % 60
    }

    //simplified to what OP wanted
    var hoursMinutesAndSeconds: (hours: Int, minutes: Int, seconds: Int) {
        return (hours, minutes, seconds)
    }
}

let watch = StopWatch(totalSeconds: 27005 + 31536000 + 86400)
print(watch.years) // Prints 1
print(watch.days) // Prints 1
print(watch.hours) // Prints 7
print(watch.minutes) // Prints 30
print(watch.seconds) // Prints 5
print(watch.hoursMinutesAndSeconds) // Prints (7, 30, 5)

这样的方法允许添加如下的方便解析：

extension StopWatch {

    var simpleTimeString: String {
        let hoursText = timeText(from: hours)
        let minutesText = timeText(from: minutes)
        let secondsText = timeText(from: seconds)
        return "\(hoursText):\(minutesText):\(secondsText)"
    }

    private func timeText(from number: Int) -> String {
        return number < 10 ? "0\(number)" : "\(number)"
    }
}
print(watch.simpleTimeString) // Prints 07:30:05

应该注意的是，纯粹基于整数的方法不考虑闰日/秒。如果用例处理实际日期/时间Date，则应使用Calendar。

Answer 6

Swift 4

import boto3

s3 = boto3.resource('s3')

bucket_name = 'bucketnamehere'

for bucket in s3.buckets.all():
    print(bucket.name)

Answer 7

这是Swift3中的另一个简单实现。

func seconds2Timestamp(intSeconds:Int)->String {
   let mins:Int = intSeconds/60
   let hours:Int = mins/60
   let secs:Int = intSeconds%60

   let strTimestamp:String = ((hours<10) ? "0" : "") + String(hours) + ":" + ((mins<10) ? "0" : "") + String(mins) + ":" + ((secs<10) ? "0" : "") + String(secs)
   return strTimestamp
}

Answer 8

SWIFT 3.0解决方案大致基于上面使用扩展的解决方案。

extension CMTime {
  var durationText:String {
    let totalSeconds = CMTimeGetSeconds(self)
    let hours:Int = Int(totalSeconds.truncatingRemainder(dividingBy: 86400) / 3600)
    let minutes:Int = Int(totalSeconds.truncatingRemainder(dividingBy: 3600) / 60)
    let seconds:Int = Int(totalSeconds.truncatingRemainder(dividingBy: 60))

    if hours > 0 {
        return String(format: "%i:%02i:%02i", hours, minutes, seconds)
    } else {
        return String(format: "%02i:%02i", minutes, seconds)
    }

  }
}

将它与AVPlayer一起调用就好吗？

 let dTotalSeconds = self.player.currentTime()
 playingCurrentTime = dTotalSeconds.durationText

Answer 9

如果应用程序的目标是iOS 10.0或更高版本，则可以使用Measurement将秒数转换为小时，分钟和秒。在Swift 4.2.1 / Xcode 10.1中，您可以使用此函数将单位持续时间的值转换为秒：

func convert<MeasurementType: BinaryInteger>(measurementValue: MeasurementType,
                                             unitDuration: UnitDuration) -> (MeasurementType, MeasurementType) {
    let measurementSeconds = Measurement<UnitDuration>(value: Double(measurementValue),
                                                       unit: .seconds)
    let secondsCount = MeasurementType(measurementSeconds.converted(to: unitDuration).value)
    let measurementCurrentUnit = Measurement(value: Double(secondsCount),
                                             unit: unitDuration)
    let currentUnitCount = MeasurementType(measurementCurrentUnit.converted(to: .seconds).value)
    return (secondsCount, measurementValue - currentUnitCount)
}

要获取所需值，只需将其调用两次即可：

func convertSecondsToHoursMinutesSeconds<MeasurementType: BinaryInteger>(seconds: MeasurementType) -> (MeasurementType, MeasurementType, MeasurementType) {
    let hoursAndRestSeconds = convert(measurementValue: seconds, unitDuration: .hours)
    let minutesAndRestSeconds = convert(measurementValue: hoursAndRestSeconds.1, unitDuration: .minutes)
    return (hoursAndRestSeconds.0, minutesAndRestSeconds.0, minutesAndRestSeconds.1)
}

如何使用它：

let result = convertSecondsToHoursMinutesSeconds(seconds: 27005)
print("\(result.0) Hours \(result.1) Minutes \(result.2) Seconds")

如您所见，我在解决方案中没有使用60、3600或其他数字常量。

Answer 10

根据 GoZoner 回答，我写了一个扩展程序，根据小时，分钟和秒数获取时间格式：

extension Double {

    func secondsToHoursMinutesSeconds () -> (Int?, Int?, Int?) {
        let hrs = self / 3600
        let mins = (self.truncatingRemainder(dividingBy: 3600)) / 60
        let seconds = (self.truncatingRemainder(dividingBy:3600)).truncatingRemainder(dividingBy:60)
        return (Int(hrs) > 0 ? Int(hrs) : nil , Int(mins) > 0 ? Int(mins) : nil, Int(seconds) > 0 ? Int(seconds) : nil)
    }

    func printSecondsToHoursMinutesSeconds () -> String {

        let time = self.secondsToHoursMinutesSeconds()

        switch time {
        case (nil, let x? , let y?):
            return "\(x) min \(y) sec"
        case (nil, let x?, nil):
            return "\(x) min"
        case (let x?, nil, nil):
            return "\(x) hr"
        case (nil, nil, let x?):
            return "\(x) sec"
        case (let x?, nil, let z?):
            return "\(x) hr \(z) sec"
        case (let x?, let y?, nil):
            return "\(x) hr \(y) min"
        case (let x?, let y?, let z?):
            return "\(x) hr \(y) min \(z) sec"
        default:
            return "n/a"
        }
    }
}

let tmp = 3213123.printSecondsToHoursMinutesSeconds() // "892 hr 32 min 3 sec"

Answer 11

@ r3dm4n的

Answer很不错。但是，我还需要一个小时。以防万一有人也需要它：

func formatSecondsToString(_ seconds: TimeInterval) -> String {
    if seconds.isNaN {
        return "00:00:00"
    }
    let sec = Int(seconds.truncatingRemainder(dividingBy: 60))
    let min = Int(seconds.truncatingRemainder(dividingBy: 3600) / 60)
    let hour = Int(seconds / 3600)
    return String(format: "%02d:%02d:%02d", hour, min, sec)
}

Answer 12

Swift 5和字符串响应，采用可显示的格式

public static func secondsToHoursMinutesSecondsStr (seconds : Int) -> String {
      let (hours, minutes, seconds) = secondsToHoursMinutesSeconds(seconds: seconds);
      var str = hours > 0 ? "\(hours) h" : ""
      str = minutes > 0 ? str + " \(minutes) min" : str
      str = seconds > 0 ? str + " \(seconds) sec" : str
      return str
  }

public static func secondsToHoursMinutesSeconds (seconds : Int) -> (Int, Int, Int) {
        return (seconds / 3600, (seconds % 3600) / 60, (seconds % 3600) % 60)
 }

用法：

print(secondsToHoursMinutesSecondsStr(seconds: 20000)) // Result = "5 h 33 min 20 sec"

Answer 13

最简单的方式imho：

let hours = time / 3600
let minutes = (time / 60) % 60
let seconds = time % 60
return String(format: "%0.2d:%0.2d:%0.2d", hours, minutes, seconds)

Answer 14

NSTimeInterval Double是通过扩展做的。例如：

extension Double {

    var formattedTime: String {

        var formattedTime = "0:00"

        if self > 0 {

            let hours = Int(self / 3600)
            let minutes = Int(truncatingRemainder(dividingBy: 3600) / 60)

            formattedTime = String(hours) + ":" + (minutes < 10 ? "0" + String(minutes) : String(minutes))
        }

        return formattedTime
    }
}

Answer 15

在Swift 5中：

    var i = 9897

    func timeString(time: TimeInterval) -> String {
        let hour = Int(time) / 3600
        let minute = Int(time) / 60 % 60
        let second = Int(time) % 60

        // return formated string
        return String(format: "%02i:%02i:%02i", hour, minute, second)
    }

调用函数

    timeString(time: TimeInterval(i))

将返回 02:44:57

Answer 16

最新代码：XCode 10.4 Swift 5

extension Int {
    func timeDisplay() -> String {
        return "\(self / 3600):\((self % 3600) / 60):\((self % 3600) % 60)"
    }
}

Answer 17

我继续为此创建了一个闭包（在Swift 3中）。

let (m, s) = { (secs: Int) -> (Int, Int) in
        return ((secs % 3600) / 60, (secs % 3600) % 60) }(299)

这将给出m = 4和s = 59.因此您可以根据需要格式化。如果没有更多信息，您当然也可以添加小时数。

Answer 18

Swift 4我使用此扩展程序

 extension Double {

    func stringFromInterval() -> String {

        let timeInterval = Int(self)

        let millisecondsInt = Int((self.truncatingRemainder(dividingBy: 1)) * 1000)
        let secondsInt = timeInterval % 60
        let minutesInt = (timeInterval / 60) % 60
        let hoursInt = (timeInterval / 3600) % 24
        let daysInt = timeInterval / 86400

        let milliseconds = "\(millisecondsInt)ms"
        let seconds = "\(secondsInt)s" + " " + milliseconds
        let minutes = "\(minutesInt)m" + " " + seconds
        let hours = "\(hoursInt)h" + " " + minutes
        let days = "\(daysInt)d" + " " + hours

        if daysInt          > 0 { return days }
        if hoursInt         > 0 { return hours }
        if minutesInt       > 0 { return minutes }
        if secondsInt       > 0 { return seconds }
        if millisecondsInt  > 0 { return milliseconds }
        return ""
    }
}

使用率

// assume myTimeInterval = 96460.397    
myTimeInteval.stringFromInterval() // 1d 2h 47m 40s 397ms

Answer 19

以下是我在Swift 4+中使用音乐播放器的内容。我将秒 Int 转换为可读的 String 格式

extension Int {
    var toAudioString: String {
        let h = self / 3600
        let m = (self % 3600) / 60
        let s = (self % 3600) % 60
        return h > 0 ? String(format: "%1d:%02d:%02d", h, m, s) : String(format: "%1d:%02d", m, s)
    }
}

像这样使用：

print(7903.toAudioString)

输出：2:11:43

Answer 20

neek's answer不正确。

这是正确的版本

func seconds2Timestamp(intSeconds:Int)->String {
   let mins:Int = (intSeconds/60)%60
   let hours:Int = intSeconds/3600
   let secs:Int = intSeconds%60

   let strTimestamp:String = ((hours<10) ? "0" : "") + String(hours) + ":" + ((mins<10) ? "0" : "") + String(mins) + ":" + ((secs<10) ? "0" : "") + String(secs)
   return strTimestamp
}

Answer 21

另一种方法是将秒转换为日期，并从日期本身获取秒，分钟和小时。此解决方案仅限于23:59:59

Answer 22

将数字转换为字符串形式的时间

func convertToHMS(number: Int) -> String {
  let hour    = number / 3600;
  let minute  = (number % 3600) / 60;
  let second = (number % 3600) % 60 ;
  
  var h = String(hour);
  var m = String(minute);
  var s = String(second);
  
  if h.count == 1{
      h = "0\(hour)";
  }
  if m.count == 1{
      m = "0\(minute)";
  }
  if s.count == 1{
      s = "0\(second)";
  }
  
  return "\(h):\(m):\(s)"
}
print(convertToHMS(number:3900))

Swift - 整数转换为小时/分钟/秒

22 个答案:

最新代码：XCode 10.4 Swift 5