Question

我正在制作食谱书，目前我有能力创建食谱，但现在我开始构建搜索和显示存储食谱的模块。

目前我有一个.txt文档，内容如下：

Williams Special Recipe

成分：
     面包：120克   黄油：1234克

食谱供应：12

然后我询问用户他们服务的数量，并根据配方的服务量，我需要将所有配料数量乘以该数量。然后，我需要再次使用完整的配方打印出来。

我想知道如何实现这一结果，而不是专门要求编码响应作为答案，但我非常感谢我将如何处理此任务以及所需的任何特定功能。

到目前为止，我还包含了我的代码，我很欣赏它目前非常难以理解，并且可能很难理解，但我将其包含在内以供参考。

（我还创建了一个所有已创建食谱的.txt文件，稍后将其作为一种向用户显示所有食谱的方式实现，但此时它只是设置用于搜索。）

#Recipe Task

import os.path

def file_(n):
    if n == "listR" :
        list_f = open("list_recipes.txt", "a+")
        list_f.write(new_name + "\n")
    if n == "oar": #open append read
        f=open(new_name + ".txt","a+")
    elif n == "c": #closes file
        f.close()


def print_line(x): #ease of printing multiple lines to break up text
    for c in range(x):
        print ""

def new_ingredients(): #adding new ingredients
    f.write("Ingredients:" + "\n" + "\n")
    fin_ingredient = False
    while fin_ingredient != True :
        input_ingredient = raw_input("New ingredient:" + "\n").lower()
        split_ingred = input_ingredient.split()
        if input_ingredient == "stop": #stops asking questions when user types 'stop'
            fin_ingredient = True
        else :
            f.write(split_ingred[0] + ":" + "  " + split_ingred[1] + " " + split_ingred[2] + "\n")

def search_recipe(n): #searching for recipes
    n = n + ".txt"
    if os.path.isfile('/Users/wjpreston/Desktop/' + n) == True :
        print "Recipe Found..."
        found_recipe = open(n)
        print found_recipe.read()
        append_serving = raw_input("Would you like to change the number of people you are serving?" + "\n").lower()
        if append_serving == "yes" :
            appended_serving = input("How many would you like to serve?" + "\n")

            with open(n) as f:  #here is my issue - not sure where to go with this!!
                list_recipe = f.readlines()   

            found_recipe.close()
        else :
            print "fail"



    else:
        print "No existing recipes under that name have been found."







print "Welcome to your Recipe Book"
print_line(3)

recipe_phase = raw_input("Are you 'creating' a recipe or 'viewing' an existing one?" + "\n").lower()

if recipe_phase == "creating":

    new_name = raw_input("Name of Recipe: " + "\n")
    file_("listR")
    file_("oar")
    f.write("------------" + "\n" + new_name + "\n" + "\n")
    print "Ingrediants required in the format 'ingredient quantity unit' - type 'stop' to end process"
    new_ingredients()
    new_num = input("Number serving:    ")
    f.write("\n" + "Recipe Serves: " + str(new_num) + "\n" "\n" + "\n")
    file_("c")



elif recipe_phase == "viewing":
    search = raw_input("Search for recipe: ")
    search_recipe(search)

Answer 1

我不是处理字符串的专家，但我会按照以下方式处理你的问题：
将每种成分保存在新生产线上用“\ n”拆分加载的字符串。
然后使用一些for循环处理列表，同时创建两个dicts，一个用于实际数据

 e.g. {"bread": 4, "butter": 7}

和每种成分的类型之一：

 e.g. {"bread": grams, "butter": grams}

您还应该保存为食谱编写的服务数量，以及成分的顺序（dicts以随机顺序存储）：

e.g. ["bread", "butter"]

之后，您可以询问您的客户他有多少服务，然后最终计算并打印最终结果。

   for ing in ing_order:
       print ing+":", ing_amount[ing]*requested_serves/default_seves, ing_types[ing]

......你仍然有足够的挑战，希望我能正确理解你的问题。

返回文本文件的内容并打印不同的值

1 个答案: