Question

我有2张桌子，＆＃39;部门＆＃39;和＆＃39;文件＆＃39;。

表department

| doc_id |      dept_name        |
----------------------------------
|      1 | Information Technology| 
|      2 | Software Development  | 
|      3 | Human Resource        |  
|      4 | Accounting            | 
|      5 | Support               |

表document

| doc_id | doc_name    | author    |  description | department             |
----------------------------------------------------------------------------
|      1 | Maps        |  User1    |  sample      | Information Technology |
|      2 | Audits      |  User3    |  sample      | Software Development   |
|      3 | Image       |  User1    |  sample      | Information Technology |
|      4 | Papers      |  User4    |  sample      | Human Resource         |
|      5 | Print Screen|  User1    |  sample      | Software Development   |
|      6 | Transaction |  User3    |  sample      | Accounting             |
|      7 | Graph       |  User1    |  sample      | Support                |
|      8 | Excel       |  User1    |  sample      | Information Technology |

现在，我想显示包含两列的表：department和total_doc。

输出：

|      department       |total_doc|
-----------------------------------
| Information Technology| 3       |
| Software Development  | 2       |
| Human Resource        | 1       |
| Accounting            | 1       |
| Support               | 1       |

我想在部门内显示整个文档，并按升序排列。

这是我的疑问。（不确定）

SELECT department, count(doc_name) as 'total_doc' FROM tbl_document GROUP BY doc_name

我在Codeigniter中使用MVC模式。

$this->db->select("department, count(doc_name) as 'total_doc'");
$this->db->from('document');
$this->db->group_by('doc_name');

另外，如何在表格中显示？喜欢在html中使用foreach吗？

Answer 1

您需要使用department而不是doc_name进行分组。

$this->db->select("department, count(doc_name) as 'total_doc'");
$this->db->from('document');
$this->db->group_by('department');
$result = $this->db->get()->result();

希望这会对你有帮助。

foreach ($result as $row)
{
    echo $row->department."----".$row->total_doc;
}

Answer 2

你去吧

SELECT dept_name,COUNT(td.department) FROM department d
LEFT JOIN tdocument td ON td.`department`=d.`dept_name`
GROUP BY td.`department` ORDER BY COUNT(td.`department`) DESC;

Answer 3

您希望每个部门一行。 IN SQL词：您希望按部门分组。

select department, count(*) as total_doc from document group by department;

（顺便说一句：不要对列别名使用单引号。）

如何计算具有相同列数据的行数并显示到表中？

3 个答案: