Question

我有这个SQL查询

   $query="SELECT * FROM FLIGHTTABLE INNER JOIN AirplaneTable ON FLIGHTTABLE.AIRPLANEID = AirplaneTable.AIRPLANEID
    INNER JOIN AIRPORTTABLE from_airport ON FLIGHTTABLE.AIRPORTDEPARTURE = from_airport.AIRPORTID
    INNER JOIN AIRPORTTABLE to_airport ON FLIGHTTABLE.AIRPORTARRIVAL = to_airport.AIRPORTID
    INNER JOIN ROUTETABLE route ON FLIGHTTABLE.AIRPORTARRIVAL = route.TOAIRPORTID && FLIGHTTABLE.AIRPORTDEPARTURE = route.FROMAIRPORTID
    WHERE $dateofdeparture_update $dateofarrival_update $airportofdeparture_update $airportofarrival_update $id_update$seats_update $status_update;";

    $res = mysql_query($query, GetMyConnection() );
    if (!mysql_num_rows($res))
    {
    if ($id)
{
        $results = array('success' => false, 'error' => 'Este voo não foi encontrado');
        } else {
               $results = array('success' => false, 'error' => 'Nenhum voo foi encontrado');
        }
          }
        else
        {

        while($row = mysql_fetch_array($res))
            {
                //echo $row;
                $data[] = array(
                        'id'   => $row['FLIGHTID'],
                        'status'   => $row['FLIGHTSTATUS'],
                        'reason'   => $row['REASON'],
                        'airplane' => array(
                            'id' => $row['AIRPLANEID'],
                            'name' => $row['NAME']
                        ),
                        'departure' => $row['DATEOFDEPARTURE'],
                        'arrival' => $row['DATEOFARRIVAL'],
                        'fromairport' => $row['AIRPORTDEPARTURE'],
                        'fromairportname' => $row['NAMEOFAIRPORT'],
                        'toairport' => $row['AIRPORTARRIVAL'],
                        'toairportname' => $row['NAMEOFAIRPORT'],
                        'price' => $row['PRICE'],
                        'availableseats' => $row['AVAILABLESEATS'],
                        'price' => $row['PRICE'],
                        'photo' => $row['PHOTO'],
                );
            }

        $results = array('success' => true, 'data' => $data);

虽然'fromairportname'和'toairportname'应该具有不同的值，但它们具有相同的值，因为$row['NAMEOFAIRPORT']具有相同的值。如何获得第二个内连接的$row['NAMEOFAIRPORT']，以便它们显示实际的出发和到达数据？

由于

Answer 1

$query="SELECT FLIGHTTABLE.FLIGHTID, 
        FLIGHTSTATUS, 
        REASON, 
        FLIGHTTABLE.AIRPLANEID, 
        DATEOFDEPARTURE, 
        DATEOFARRIVAL, 
        AIRPORTDEPARTURE, 
        from_airport.NAMEOFAIRPORT AS TONAMEOFAIRPORT, 
        AIRPORTARRIVAL, 
        to_airport.NAMEOFAIRPORT AS FROMNAMEOFAIRPORT,

重命名像from_airport.NAMEOFAIRPORT AS TONAMEOFAIRPORT这样的列解决了这个问题。

全部感谢您的帮助

Answer 2

而不是选择*＆＃39;您必须为查询中的每一列命名。然后你可以将它们别名为PHP独有/可用的东西。

SELECT FLIGHTID, FLIGHTSTATUS, REASON, ...,
    AIRPORTDEPARTURE.NAMEOFAIRPORT fromAirport, AIRPORTARRIVAL.NAMEOFAIRPORT toAirport, ... 
   FROM FLIGHTTABLE

等等

如何访问具有相同名称的PHP表元素

2 个答案: