有人可以指导我找到解决以下问题的方法。
我已从google doc读取 ContactsContract.Groups,其中包含有关原始联系人群组(如Gmail联系人群组)的信息。当前的API不支持跨多个帐户的组的概念。
基于此,我尝试了以下代码。
StringBuffer output = new StringBuffer();
final String[] GROUP_PROJECTION = new String[] {
ContactsContract.Groups._ID,
ContactsContract.Groups.TITLE,
ContactsContract.Groups.SUMMARY_WITH_PHONES
};
Cursor c = getContentResolver().query(
ContactsContract.Groups.CONTENT_URI, GROUP_PROJECTION, null,
null, ContactsContract.Groups.TITLE);
int IDX_ID = c.getColumnIndex(ContactsContract.Groups._ID);
int IDX_TITLE = c.getColumnIndex(ContactsContract.Groups.TITLE);
output.append("title"+IDX_TITLE+"\n");
Map<String,GroupInfo> m = new HashMap<String, GroupInfo>();
while (c.moveToNext()) {
output.append("test...\n");
GroupInfo g = new GroupInfo();
g.id = c.getString(IDX_ID);
g.title = c.getString(IDX_TITLE);
output.append("title"+c.getString(IDX_TITLE)+"\n");
int users = c.getInt(c.getColumnIndex(ContactsContract.Groups.SUMMARY_WITH_PHONES));
if (users>0) {
// group with duplicate name?
GroupInfo g2 = m.get(g.title);
if (g2==null) {
m.put(g.title, g);
output.append("title"+g.title+"\n");
groups.add(g);
} else {
g2.id+=","+g.id;
}
}
}
outputText.setText(output);
c.close();
但没有希望。
答案 0 :(得分:2)
我发布此答案以备将来使用。我们可以使用名为RawContacts.SOURCE_ID
描述here
<强> SOURCE_ID
读/写
将此行唯一标识为其源帐户的字符串。通常,它是在插入原始触点时设置的,之后从不更改。一个值得注意的例外是新的原始联系人:它将具有帐户名称和类型(可能还有数据集),但没有源ID。这向同步适配器指示需要在服务器端创建新联系人,并将其ID存储在电话上相应的SOURCE_ID字段中。
示例代码如下,它为同步联系人提供id,为其他人提供null。
private void testContact() {
StringBuffer output = new StringBuffer();
ContentResolver resolver = getContentResolver();
Cursor contacts = resolver.query(Contacts.CONTENT_URI, null,
Contacts.HAS_PHONE_NUMBER + " != 0", null, Contacts._ID
+ " ASC");
Cursor data = resolver.query(Data.CONTENT_URI, null, Data.MIMETYPE
+ "=? OR " + Data.MIMETYPE + "=?", new String[]{
Email.CONTENT_ITEM_TYPE, Phone.CONTENT_ITEM_TYPE},
Data.CONTACT_ID + " ASC");
int idIndex = contacts.getColumnIndexOrThrow(Contacts._ID);
int nameIndex = contacts.getColumnIndexOrThrow(Contacts.DISPLAY_NAME);
int cidIndex = data.getColumnIndexOrThrow(Data.CONTACT_ID);
int data1Index = data.getColumnIndexOrThrow(Data.DATA1);
boolean hasData = data.moveToNext();
while (contacts.moveToNext()) {
long id = contacts.getLong(idIndex);
Uri rawContactUri =
ContentUris.withAppendedId(RawContacts.CONTENT_URI, id);
Uri entityUri =
Uri.withAppendedPath(rawContactUri, Entity.CONTENT_DIRECTORY);
Cursor c =
getContentResolver().query(
entityUri,
new String[] {
RawContacts.ACCOUNT_NAME,
RawContacts.SOURCE_ID, Entity.DATA_ID, Entity.MIMETYPE, Entity.DATA1},
null, null, null);
try {
while (c.moveToNext()) {
String sourceId = c.getString(0);
if (!c.isNull(1)) {
String source_id = c.getString(1);
try {
output.append(c.getString(4)+sourceId+" "+source_id+"\n");
//output.append(datas+ "Sync1 "+ c.getString(4)+" Sync2 "+ c.getString(5)+" Sync3"+ c.getString(6)+" Sync4 "+ c.getString(7)+"\n");
} catch (Exception e) {
e.printStackTrace();
}
//decide here based on mimeType, see comment later
}
}
} finally {
c.close();
}
}
outputText.setText(output);
}
答案 1 :(得分:1)
仔细阅读this并查看ACCOUNT_TYPE
是否可以为您提供帮助