Question

我正在使用此脚本来比较php中的两个日期列。我有图像文件夹，并希望将所有符合日期的图像合并为一个xml。图片格式为“entry_145_BD12ZZU_2014-06-25_12-26-58”.jpg

 if(file_exists($xmlFullFilename)) {
if($entryTimeNode->format("Y-m-d") = $entryTimeNode->format("Y-m-d"))** this is what I tried.
            $xmlDoc = new DomDocument();
            $tmp = split(" ", $entryTime);
        $dateString = $tmp[0] . "T" . $tmp[1];
        $entryTimeNode = $xmlDoc->createElement("EntryTime", $dateString);

XML文件

    <Incidents xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" Count="2" Date="2014-10-24" Time="12:05:39" FileName="2014-10-24_Brook_Retail_Park.xml">
      <Incident>
      <EntryTime>**2014-10-17**T11:17:44</EntryTime>
      </Incident>
    <Incident>
<EntryTime>**2014-10-17**T16:19:15</EntryTime>
</Incident></Incidents>

Answer 1

mostly date also compare with as like normal variable like: 

$a=5;
$b=10;
if($a > $b){
 //Blalala
}

and in date also you can compare like this
$c=2014/10/29;
$d=2014/10/29;
if($c > $d){
 //Blalala
}

and i can't more figure out from question you have date with time so in your case,
$e=**2014-10-17**T11:17:44
$f=**2014-10-17**T16:19:15

$first_date_ary=explode("**", $e);
$second_date_ary=explode("**", $f);

and then compare your date, as per i mention above
if($first_date_ary[0] > $second_date_ary[0]){
 //Blalala
}

and sorry for bad English too.

在php中比较两个日期值而不是时间

1 个答案: