Question

我对这件事很新。我只是想知道是否有可能获得Web套接字客户端请求标头。我的意思是来自客户端的头部用于握手。提前谢谢！
对不起，如果我问的问题不清楚我想要的是获得这样的标题格式：

GET ws://websocket.example.com/ HTTP/1.1
Origin: http://example.com
Connection: Upgrade
Host: websocket.example.com
Upgrade: websocket

Answer 1

请参阅：apache_request_headers

<?php
$headers = apache_request_headers();

foreach ($headers as $header => $value) {
    echo "$header: $value <br />\n";
}
?>

如果不将php作为apache模块运行，则可以使用predefined $_SERVER variable：

foreach ($_SERVER as $header => $value) {
    echo "$header: $value <br />\n";
}

上面应该返回如下所示的内容：

HTTP_HOST: testdrive 
HTTP_CONNECTION: keep-alive 
HTTP_CACHE_CONTROL: max-age=0 
HTTP_ACCEPT: text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8 
HTTP_USER_AGENT: Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/38.0.2125.104 Safari/537.36 
HTTP_ACCEPT_ENCODING: gzip,deflate,sdch 
HTTP_ACCEPT_LANGUAGE: nl,en-US;q=0.8,en;q=0.6 
HTTP_COOKIE: __atuvc=1%7C8

如何从客户端获取使用php的套接字的头请求

1 个答案: