我遇到了JApplet
的问题。目前我有CardLayout
JPanel
,其中包含两个BorderLayout
JPanel
个。每当我运行它时,组件都会添加到每张卡片中。 (JButton
返回到另一个JPanel
),除非我对每个setVisible(true)
使用LayoutManager
,否则不会显示。此外,我的ActionListener
都没有工作。我之所以假设是因为他们只使用show()
,而且还有别的东西我必须这样做,并且暗指我。
我必须使用setVisible(true)
吗?从其他问题来看,似乎有一种方法可以做到这一点。以下是我遇到问题的代码:
/*
*Java Version: 1.8.0_25
*Author: Peadar Ó Duinnín
*Student Number: R00095488
*/
package As1;
import java.awt.BorderLayout;
import java.awt.CardLayout;
import java.awt.Color;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.JApplet;
import javax.swing.JButton;
import javax.swing.JLabel;
import javax.swing.JPanel;
public class AUIJApplet extends JApplet implements ActionListener {
private final int WIDTH = 600;
private final int HEIGHT = 400;
private int highScore;
private int currentScore;
JPanel panelCont = new JPanel();
JPanel startPanel = new JPanel();
JPanel gamePanel = new JPanel();
JButton newGameButton = new JButton("New Game");
JButton endGameButton = new JButton("End Game");
JLabel highScoreLabel;
JLabel currentScoreLabel;
CardLayout cl = new CardLayout();
BorderLayout bl = new BorderLayout();
public AUIJApplet() {
highScore = 0;
}
@Override
public void init() {
setSize(WIDTH, HEIGHT);
panelCont.setLayout(cl);
startPanel.setLayout(bl);
gamePanel.setLayout(bl);
startPanel.add(newGameButton, BorderLayout.SOUTH);
gamePanel.add(endGameButton, BorderLayout.SOUTH);
startPanel.setBackground(Color.BLUE);
gamePanel.setBackground(Color.GREEN);
panelCont.add(startPanel, "Start Applet Screen");
panelCont.add(gamePanel, "New Game Screen");
newGameButton.addActionListener((e) -> {
newGame();
});
endGameButton.addActionListener((e) -> {
quitGame();
});
cl.show(panelCont, "Start Applet Screen");
this.add(panelCont);
}
public void newGame() {
cl.show(panelCont, "New Game Screen");
showScores(gamePanel);
}
public void quitGame() {
cl.show(panelCont, "Start Applet Screen");
if (currentScore > highScore) {
highScore = currentScore;
}
currentScore = 0;
}
public void showScores(JPanel currentPanel) {
currentPanel.add(new JLabel("High Score:") , BorderLayout.EAST);
currentPanel.add(highScoreLabel, BorderLayout.EAST);
currentPanel.add(new JLabel("Current Score:"), BorderLayout.EAST);
currentPanel.add(currentScoreLabel, BorderLayout.EAST);
}
@Override
public void actionPerformed(ActionEvent ae) {
}
}
答案 0 :(得分:2)
我已经制作了一个类似的代码来执行相同的操作,它适用于我尝试从头开始编写代码。这是我的代码。
import java.awt.BorderLayout;
import java.awt.CardLayout;
import java.awt.Color;
import java.awt.event.ActionEvent;
import javax.swing.JApplet;
import javax.swing.*;
public class Example extends JApplet {
JPanel panel1,panel2,mainPanel;
JButton start,stop;
CardLayout cl = new CardLayout();
@Override
public void init() {
panel1 = new JPanel();
panel1.setBackground(Color.red);
panel1.setLayout(new BorderLayout());
panel2 = new JPanel();
panel2.setBackground(Color.blue);
panel2.setLayout(new BorderLayout());
start = new JButton("Start");
stop = new JButton("stop");
panel1.add(start,BorderLayout.SOUTH);
panel2.add(stop,BorderLayout.SOUTH);
mainPanel = new JPanel();
mainPanel.setLayout(cl);
mainPanel.add(panel1,"First Panel");
mainPanel.add(panel2, "Second Panel");
start.addActionListener((ActionEvent e) -> {
newGame();
});
stop.addActionListener((ActionEvent e) ->{
endGame();
});
this.add(mainPanel);
}
public void newGame()
{
cl.show(mainPanel, "Second Panel");
}
public void endGame()
{
cl.show(mainPanel,"First Panel");
}
}