Question

我有一系列篮球运动员，每个球员都有一个数组，其中包含以下数据：

[[893, "Jordan, Michael", 0, "1984", "2002", "michael_jordan"],[674, "Doe, John", 0, "2009", "2014", "doe_john"]]

我想过滤这个数组，只显示数组中有"2014"年的玩家，这样我就可以获得所有活跃玩家的列表。

以下是我现在尝试的代码：

players =  [[893, "Jordan, Michael", 0, "1984", "2002", "michael_jordan"],[674, "Doe, John", 0, "2009", "2014", "doe_john"]]
active = set('2014')
for player in players:
     if players & set(active):
          print active

控制台中的错误是：

    Traceback (most recent call last):
  File "<stdin>", line 2, in <module>
TypeError: unsupported operand type(s) for &: 'list' and 'set'

任何人都可以帮我解决这个问题吗？我真的很感激！

Answer 1

active是一个集合，但player是一个列表。使用&仅适用于两个设置对象，而不是列表和集合。

但是，您首先不应该使用集合，因为您只想查看字符串是否在列表中。为此，您应该使用简单的in membership test：

players =  [[893, "Jordan, Michael", 0, "1984", "2002", "michael_jordan"],[674, "Doe, John", 0, "2009", "2014", "doe_john"]]
active = '2014'
for player in players:
     if active in player:
          print active

如果active in player位于列表True中，

'2014'将返回player。以下是演示：

>>> active = '2014'
>>> player = [893, "Jordan, Michael", 0, "1984", "2002", "michael_jordan"]
>>> active in player
False
>>> player = [674, "Doe, John", 0, "2009", "2014", "doe_john"]
>>> active in player
True
>>>

按字符串过滤列表中的列表

1 个答案: