Question

我有一组数据。我想按＆＃34; Name =＆＃34;排序。行并在每个＆＃34; Name =＆＃34;下面有正确的数据集。这可能吗？我查看了排序参考，但没有找到任何有关此物流的信息。我得到的数据量低于每个＆＃34; Name =＆＃34;可以是完全不同的。

我试图用man sort来找到解决这个问题的工具，但我似乎找不到这样的东西。先感谢您。我可能正在使用不正确的工具或命令。

我目前的数据集。我有数千行具有类似数据。

Name=Sally15 
Kitty Up Count 10 Active 1
Trex Up Count 5 Active 1
Name=Bob14
Bird Up Count 10 Active 5
Dog Up Count 2 Active 3 
Trex Up Count 5 Active 1
Name=Sally12 
Cow Up Count 5 Active 1
Trex Up Count 5 Active 2
Name=Bob13 
Cow Up Count 5 Active 1

欲望结果

Name=Bob13 
Cow Up Count 5 Active 1
Name=Bob14
Bird Up Count 10 Active 5
Dog Up Count 2 Active 3 
Trex Up Count 5 Active 1
Name=Sally12 
Cow Up Count 5 Active 1
Trex Up Count 5 Active 2
Name=Sally15 
Kitty Up Count 10 Active 1
Trex Up Count 5 Active 1

我的服务器上发生了什么

(admin)$ cat file
Name=Sally15
Kitty Up Count 10 Active 1
Trex Up Count 5 Active 1
Name=Bob14
Bird Up Count 10 Active 5
Dog Up Count 2 Active 3
Trex Up Count 5 Active 1
Name=Sally12
Cow Up Count 5 Active 1
Trex Up Count 5 Active 2
Name=Bob13
Cow Up Count 5 Active 1
[admins01:/script/users/admin]
(admin)$ gawk -v RS='Name=' '
    NR>1 {record[$1]=$0}
    END {
        PROCINFO["sorted_in"]="@ind_str_asc"
        for (key in record) printf "%s%s", RS, record[key]
    }
' file
Name=Sally12
Cow Up Count 5 Active 1
Trex Up Count 5 Active 2
Name=Bob13
Cow Up Count 5 Active 1
Name=Sally15
Kitty Up Count 10 Active 1
Trex Up Count 5 Active 1
Name=Bob14
Bird Up Count 10 Active 5
Dog Up Count 2 Active 3
Trex Up Count 5 Active 1

Answer 1

我打赌你的gawk版本是“老”。试试这个perl：

perl -0777 -ne 'print join "", sort split /^(?=Name=)/m' file

GNU awk：使用“Name =”作为记录分隔符，并按记录的第一个单词排序。

gawk -v RS='Name=' '
    NR>1 {record[$1]=$0} 
    END {
        PROCINFO["sorted_in"]="@ind_str_asc"
        for (key in record) printf "%s%s", RS, record[key]
    }
' file

请注意，这将使用词典排序，因此“Bob10”将在“Bob1”和“Bob2”之间排序

测试：

$ cat file Name=Sally15 Kitty Up Count 10 Active 1 Trex Up Count 5 Active 1 Name=Bob14 Bird Up Count 10 Active 5 Dog Up Count 2 Active 3 Trex Up Count 5 Active 1 Name=Sally12 Cow Up Count 5 Active 1 Trex Up Count 5 Active 2 Name=Bob13 Cow Up Count 5 Active 1 $ gawk -v RS='Name=' ' NR>1 {record[$1]=$0} END { PROCINFO["sorted_in"]="@ind_str_asc" for (key in record) printf "%s%s", RS, record[key] } ' file Name=Bob13 Cow Up Count 5 Active 1 Name=Bob14 Bird Up Count 10 Active 5 Dog Up Count 2 Active 3 Trex Up Count 5 Active 1 Name=Sally12 Cow Up Count 5 Active 1 Trex Up Count 5 Active 2 Name=Sally15 Kitty Up Count 10 Active 1 Trex Up Count 5 Active 1

Unix的。在行上对一组数据进行排序

1 个答案: