我的日期格式为: woensdag 22 oktober 2014 08:41:42
我希望将此日期转换为 dd-mm-yyyy 格式,以便生成日期为22-10-2014。日期是荷兰语。
如何使用PHP
转换它答案 0 :(得分:1)
我必须为它写一个基本字典,但这里是:
function dutch_strtotime($datetime) {
$days = array(
"maandag" => "Monday",
"dinsdag" => "Tuesday",
"woensdag" => "Wednesday",
"donderdag" => "Thursday",
"vrijdag" => "Friday",
"zaterdag" => "Saturday",
"zondag" => "Sunday"
);
$months = array(
"januari" => "January",
"februari" => "February",
"maart" => "March",
"april" => "April",
"mei" => "May",
"juni" => "June",
"juli" => "July",
"augustus" => "August",
"september" => "September",
"oktober" => "October",
"november" => "November",
"december" => "December"
);
$array = explode(" ", $datetime);
$array[0] = $days[strtolower($array[0])];
$array[2] = $months[strtolower($array[2])];
return strtotime(implode(" ", $array));
}
$date = "woensdag 22 oktober 2014 08:41:42";
echo date("l d-m-Y H:i:s", dutch_strtotime($date)) . "<br />";
echo date("d-m-Y", dutch_strtotime($date));
PHPFiddle链接:http://phpfiddle.org/main/code/k51z-9n6j