Question

我试图获得business_id＆＃39;和＆＃39;评级＆＃39;从表格＆＃39;评论＆＃39;在哪里＆＃39; review_id＆＃39;是$ approveReviewID

然后更新＆＃39;评分＆＃39;在＆＃39; business_details＆＃39;来自＆＃39;评论＆＃39;的检索评级其中＆＃39; business_id＆＃39;等于检索到的。

我有这两个问题，

SELECT business_id, rating FROM reviews WHERE review_id = '$approveReviewID';

UPDATE business_details SET rating = rating + $rating WHERE business_id = '$businessID';

有没有办法将这些查询加入一个？

Answer 1

是的，您可以使用update-join语法：

UPDATE business_details bd
JOIN   reviews r ON bd.business_id = r.business_id
SET    bd.rating = bd.rating + r.rating
WHERE  r.review_id = '$approveReviewID'

Answer 2

在from子句中使用简单的“内连接”来连接两个表

UPDATE  bd
SET     rating = bd.rating + rvs.rating
FROM    reviews rvs
        INNER JOIN business_details bd ON db.business_id = rvs.business_id
WHERE   rvs.review_id = '$approveReviewID'

从表中选择并更新另一个表SQL

2 个答案: