Question

我正在尝试创建一个报告查询，显示给定的日期范围，所有名称，日期以及是否有数据。我真的很接近，但我对如何在数据中获得这些最终零值感到茫然。所以这就是我想要的：

 Name   ID     Mth Day Count
 Auburn  7261   10  14  0
 Auburn  7261   10  15  0
 Auburn  7261   10  16  0
 Auburn  7261   10  17  0
 Auburn  7261   10  18  0
 Concord 7262   10  14  2
 Concord 7262   10  15  0
 Concord 7262   10  15  0
 Concord 7262   10  17  1
 Katey   7263   10  14  0
 Katey   7263   10  15  0
 Katey   7263   10  16  0
 Katey   7263   10  17  0
 Katey   7263   10  18  0

相反，我得到了：

 Name   ID     Mth Day Count
 Auburn  7261   10  14  0
 Auburn  7261   10  15  0
 Auburn  7261   10  16  0
 Auburn  7261   10  17  0
 Auburn  7261   10  18  0
 Concord 7262   10  14  2
 Concord 7262   10  17  1
 Katey   7263   10  14  0
 Katey   7263   10  15  0
 Katey   7263   10  16  0
 Katey   7263   10  17  0
 Katey   7263   10  18  0

这是我的疑问：

 SELECT PUE.Name as [Name], pue.EventID,
 MONTH(dates.Date) AS Month, DAY(dates.Date) AS Day,
 puc.idcount AS PicturesTaken
 from (
 select name, eventid from Events where 
 TourID = 444 and EventID > 7256 and EventID < 7323
 ) PUE
 outer apply (
SELECT
    Date = DateAdd( Day, n1.number * 10 + n0.number, '2014-10-14' )
FROM
    (SELECT 1 AS number UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 0) as n0
CROSS JOIN
    (SELECT 1 AS number UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 0) as n1
WHERE   DateAdd( Day, n1.number * 10 + n0.number, '2014-10-14' ) BETWEEN '2014-10-14' AND '2014-10-18'
 ) dates
 left outer join (
 select eventid, convert(date,picturetakendate) as picdate, count(consumerdataid) as idcount from ConsumerData
 where EventID > 7256 and EventID < 7323 
 group by eventid, convert(date,picturetakendate)
 ) puc
 on pue.EventID = puc.EventID 
 where puc.picdate = dates.Date or puc.idcount is NULL
 order by pue.eventid, MONTH(dates.Date), DAY(dates.Date)

我明白为什么零没有显示名称，这是外连接表的结果：

 7262   2014-10-14  2
 7262   2014-10-17  1
 7265   2014-10-14  2
 7266   2014-10-14  2

因此，在where子句中，它不是null或匹配日期是有意义的。但是如果我拿出where子句，我会为每个日期的每个计数得到一行，即：。

 Concord    7262    10  14  2
 Concord    7262    10  14  1
 Concord    7262    10  15  1
 Concord    7262    10  15  2
 Concord    7262    10  16  2
 Concord    7262    10  16  1
 Concord    7262    10  17  1
 Concord    7262    10  17  2
 Concord    7262    10  18  2
 Concord    7262    10  18  1

我非常接近，我知道只有一些简单的东西，我错过了但我每次尝试修复它实际上都会让结果变得更糟，所以我来这里寻求帮助。我想我只需要修复外部联接中的查询以某种方式显示每个日期，如果我可以引用日期应用将更容易或更改在哪里。但我一直无法弄清楚如何。

Answer 1

在SELECT子句中添加ISNULL条件

 SELECT PUE.Name as [Name], pue.EventID,
 MONTH(dates.Date) AS Month, DAY(dates.Date) AS Day,
 ISNULL(puc.idcount,0) AS PicturesTaken

将where子句转换为ON

on pue.EventID = puc.EventID 
AND puc.picdate = dates.Date

而不是

where puc.picdate = dates.Date or puc.idcount is NULL

SQL Server：两个表连接显示每天没有数据的所有行

1 个答案: