我正在玩一个ArrayList,并试图让它每次超过它的大小时增长两倍。这是我的添加方法:
public class ArrayExpander
{
private int size;
private int noOfItems;
private Object[] store;
private final int INITIALSIZE = 2;
public ArrayExpander()
{
store = new Object[INITIALSIZE];
noOfItems = 0;
size = INITIALSIZE;
}
public void add(Object obj)
{
growBufferIfNecessary();
store[size++] = obj;
/*for (int i = size - 1; i < store.length; i++)
{
store[i] = store[i - 1];
store[i] = obj;
}*/
}
public String toString()
{
String temp = "[" + store[0];
for (int i = 1; i < size; i++)
{
temp = temp + "," + store[i];
}
temp = temp + "]";
return temp;
}
private void growBufferIfNecessary()
{
if (size == store.length)
{
Object[] newStore = new Object[2 * store.length];
for (int i = 0; i < store.length; i++)
{
newStore[i] = store[i];
}
store = newStore;
}
}
public static void main(String[] args)
{
ArrayExpander ae = new ArrayExpander();
//System.out.println(ae);
ae.add("a");
ae.add("b");
System.out.println(ae);
ae.add("c");
ae.add("d");
ae.add("e");
ae.add("f");
ae.add("g");
ae.add("h");
System.out.println(ae);
ae.add("i");
System.out.println(ae);
}
}
这是我的输出:
[null,null]
[null,null,a,b]
[null,null,a,b,c,d,e,f,g,h]
[null,null,a,b,c,d,e,f,g,h,i]
我无法弄清楚为什么我会得到空语句。第一行应该是a,b,然后arraylist应该加倍,并且是a,b,c,d。我把它设置为最终int INITIALSIZE = 2。 我正在寻找的输出是
[a,b]
[a,b,c,d]
[a,b,c,d,e,f,g,h]
[a,b,c,d,e,f,g,h,i,null,null,null,null,null,null,null]
答案 0 :(得分:2)
此代码适合您。 size应该是指数组的大小,而noOfItems是指数组中的项数。你有点混合2。我只在你的add()和growBufferIfNecessary()中改变了一些东西。
public class ArrayExpander
{
private int size;
private int noOfItems;
private Object[] store;
private final int INITIALSIZE = 2;
public ArrayExpander()
{
store = new Object[INITIALSIZE];
noOfItems = 0;
size = INITIALSIZE;
}
public void add(Object obj)
{
growBufferIfNecessary();
store[noOfItems++] = obj;
}
public String toString()
{
String temp = "[" + store[0];
for (int i = 1; i < size; i++)
{
temp = temp + "," + store[i];
}
temp = temp + "]";
return temp;
}
private void growBufferIfNecessary()
{
if (noOfItems == size)
{
size = 2 * size;
Object[] newStore = new Object[size];
for (int i = 0; i < store.length; i++)
{
newStore[i] = store[i];
}
store = newStore;
}
}
public static void main(String[] args)
{
ArrayExpander ae = new ArrayExpander();
//System.out.println(ae);
ae.add("a");
ae.add("b");
System.out.println(ae);
ae.add("c");
ae.add("d");
ae.add("e");
ae.add("f");
ae.add("g");
ae.add("h");
System.out.println(ae);
ae.add("i");
System.out.println(ae);
}
}
试试这个。如果你注意到我用noOfItems替换了几个斑点的大小。你真的很亲近你只需改变一些事情。
答案 1 :(得分:1)
使用循环手动复制数组非常痛苦,请使用System.arraycopy(Object,int,Object,int,int)
之类的
private int size = 0;
private Object[] store = new Object[INITIALSIZE];
private void growBufferIfNecessary() {
if (size >= store.length) {
Object[] newStore = new Object[2 * store.length];
System.arraycopy(store, 0, newStore, 0, store.length);
store = newStore;
}
}
我淘汰了noOfItems
。您不需要它,您的add
方法只是
public void add(Object obj) {
growBufferIfNecessary();
store[size++] = obj;
}
最后,您的toString()
可以使用Arrays.copyOf(T[], int)
之类的
@Override
public String toString() {
return Arrays.toString(Arrays.copyOf(store, size));
}
然后我得到了你的预期输出
[a, b]
[a, b, c, d, e, f, g, h]
[a, b, c, d, e, f, g, h, i]