Question

我正在尝试通过表单提交数据并遇到以下错误：

警告：mysql_num_rows()期望参数1为资源，布尔值为..

请找到我尝试的代码。

//connection end to my data server.

if(isset($_POST["submit"])) {

     $user_name = $_POST['name'];
     $user_email = $_POST['email'];
     $user_skype = $_POST['skype'];

    if($user_name==""){
        echo "<script>alert('please enter your user name!')</script>";
        exit();
    }

    if($user_email==""){
        echo "<script>alert('please enter your email!')</script>";
        exit();
    }       

    if($user_skype==""){
        echo "<script>alert('please enter your skype id.')</script>";
        exit();
    }   

    $check_email = "select * from binary where user_email = '$user_email' ";

    $run = mysql_query($check_email);

    if(mysql_num_rows($run)>0){

    echo "<script>alert('Your email $user_email address already exist. please try another.')</script>";
    exit();

    }

    $query= "insert into binary (user_name, user_email, user_skype) values('$user_name','$user_email','$user_skype')";

    if(mysql_query($query)){
    echo "<script>window.open('success.html','_self')</script>";
    }

}

?>

Answer 1

二进制为sql reserrve word

在其周围使用反对

$check_email = "select * from `binary` where user_email = '$user_email' ";

检查此链接是否有sql reserve word。 http://dev.mysql.com/doc/refman/5.5/en/reserved-words.html

并学习 mysqli _ 功能或 P.D.O ，因为mysql是deprcitaeted

Answer 2

请更新您的查询：它应该是

$check_email = "select * from `binary` where user_email = '".$user_email."' ";

Answer 3

似乎select查询返回布尔值false，因为

$check_email = "select * from binary where user_email = '$user_email' "

其中user_email = '$user_email'无法解析'$user_email'的值，因为单个quat中的变量未使用其值进行解析

使用： - 其中user_email =＆＃34;。$ user_email; 一切都应该有效

使用表单向服务器提交数据时出错

3 个答案: