Question

我有以下一系列词典：

dictionaty =[{'name': 'fire', 'command': '1;2;3;4'}, 
{'name': 'brain', 'command': '2;2;3;4'}, {'name': 'word', 'command': '1;3;4;5'},
{'name': 'cellphone', 'command': '6;1;3;4'}, {'name': 'ocean', 'command': '9;3;7;4'},

如何在“;”之后获取具有第二个和第三个值的命令的词典分别相等？例如：'command'：'1; 2; 3; 4'等于'command'：'2; 2; 3; 4'

Answer 1

您可以使用itertools.groupby。您可以构造一个lambda表达式，查找与'command'键对应的值，然后在[1]字符上找到分割的[2]和';'元素

d =[{'name': 'fire', 'command': '1;2;3;4'},
    {'name': 'brain', 'command': '2;2;3;4'},
    {'name': 'word', 'command': '1;3;4;5'},
    {'name': 'cellphone', 'command': '6;1;3;4'},
    {'name': 'ocean', 'command': '9;3;7;4'}]

import itertools
groups = itertools.groupby(d, lambda i: i['command'].split(';')[1:3])

for key, group in groups:
    print(list(group))

输出

[{'name': 'fire', 'command': '1;2;3;4'}, {'name': 'brain', 'command': '2;2;3;4'}]
[{'name': 'word', 'command': '1;3;4;5'}]
[{'name': 'cellphone', 'command': '6;1;3;4'}]
[{'name': 'ocean', 'command': '9;3;7;4'}]

要查找包含多个成员的组，您还需要一个步骤：

for key, group in groups:
    groupList = list(group)
    if len(groupList) > 1:
        print(groupList)

[{'command': '1;2;3;4', 'name': 'fire'}, {'command': '2;2;3;4', 'name': 'brain'}]

Answer 2

您可以迭代这些项目，并为每个项目检查要关注的项目并比较'command'的最后一部分：

dictionaty =[{'name': 'fire', 'command': '1;2;3;4'}, 
             {'name': 'brain', 'command': '2;2;3;4'}, 
             {'name': 'word', 'command': '1;3;4;5'},
             {'name': 'cellphone', 'command': '6;1;3;4'}, 
             {'name': 'ocean', 'command': '9;3;7;4'}]

for i, itm in enumerate(dictionaty):
    itm_last_part = itm['command'].split(';')[2:]
    for second in dictionaty[i+1:]:
        second_last_part = second['command'].split(';')[2:]
        if itm_last_part == second_last_part:
            print itm, second, "are equal"

<强>输出

{'command': '1;2;3;4', 'name': 'fire'} {'command': '2;2;3;4', 'name': 'brain'} are equal
{'command': '1;2;3;4', 'name': 'fire'} {'command': '6;1;3;4', 'name': 'cellphone'} are equal
{'command': '2;2;3;4', 'name': 'brain'} {'command': '6;1;3;4', 'name': 'cellphone'} are equal

如何通过匹配python中的值来对字典列表中的项进行分组

2 个答案: