Question

我现在正在学习C ++，非常新。我试图制作一个非常简单的程序，显示一个乘法表，当程序运行时，用户输入第一个数字，然后是第二个数字，程序显示表格。但问题是，当我按下键盘上的任何键时，程序退出。我希望此时程序会重复并向用户询问第一个数字。我的代码在这里：

#include <iostream>
#include <conio.h>
using namespace std;
int main(int argc,char**argv){
    int value1;
    int limit;
    int result1=1;
    int result2;
    bool runing=false;
    printf("Welcome \n");
    cout << "Please enter 1st value: " << flush;
    cin >> value1;
    cout << "Please enter a limit value: "<< flush;
    cin >> limit;
    cout<< "Result is: \n";
    while(result1<=limit){
        result2=result1*value1;
        printf("%d x %d = %d\n",value1,result1,result2);
        result1++;
    }
    return 0;
}

Answer 1

要做你想做的事，你只需要另一个while循环，在打印欢迎之后包装所有内容。像这样：

#include <iostream>
#include <conio.h>
using namespace std;
int main(int argc,char**argv){
    int value1;
    int limit;
    int result2;
    bool runing=false;
    printf("Welcome \n");
    //I don't know in which conditions you want to quit the program.
    //You could also use for() instead, to run this piece of code a certain number of times.

    while(true){
        int result1=1;
        cout << "Please enter 1st value: " << flush;
        cin >> value1;
        cout << "Please enter a limit value: "<< flush;
        cin >> limit;
        cout<< "Result is: \n";
        while(result1<=limit){
            result2=result1*value1;
            printf("%d x %d = %d\n",value1,result1,result2);
            result1++;
        }
    }
    return 0;
}

程序最后退出

1 个答案: