在构造函数中设置新屏幕无法正确显示

时间:2014-10-15 17:17:10

标签: java android libgdx

我做了一个占位符屏幕,因为它是空的我只是把它调用它的构造函数中的下一个屏幕。下一个屏幕是运行它的构造函数,但没有显示我放置的标签。当我跳过占位符屏幕并直接进入新屏幕时,它正在正确绘制它。为什么呢?

放置持有人菜单

public PlaceHolderMenu()
{
    camera = new OrthographicCamera();
    camera.setToOrtho(false, 720, 1280);
    batch = new SpriteBatch();

    skin = Assets.menuSkin;
    stage = new Stage(new FitViewport(TechnoFlux.WIDTH, TechnoFlux.HEIGHT, camera), batch);
    //No need for this screen yet so just call the next one...
    ((Game)Gdx.app.getApplicationListener()).setScreen(new GameScreen());
}

新屏幕

public GameScreen() {
    camera = new OrthographicCamera();
    camera.setToOrtho(false, 720, 1280);
    batch = new SpriteBatch();
    skin = Assets.menuSkin;
    stage = new Stage(new FitViewport(TechnoFlux.WIDTH, TechnoFlux.HEIGHT, camera), batch);

    Label test = new Label("GAMESCREEN", skin, "largetext");

    bottomUI = new Table();
    bottomUI.row();
    bottomUI.add(test);
    bottomUI.setFillParent(true);
    stage.addActor(bottomUI);

    Gdx.input.setInputProcessor(stage);
}


@Override
public void render(float delta) {
    Gdx.gl.glClearColor(.2f, .2f, .3f, 1);
    Gdx.gl.glClear(GL30.GL_COLOR_BUFFER_BIT);
    stage.act();
    stage.draw();
}

以上所有代码都在运行,但占位符介于两者之间,但未显示标签。我很确定当我向占位符屏幕添加一个指向新屏幕的按钮时,它将再次显示。我想它必须对资产加载或Screen类本身做些什么。我正在寻找对此行为的一些见解。

0 个答案:

没有答案