我需要添加“你猜对了!”但我不确定如何。有人可以向我解释如何在java中这样做吗?
我希望在最后显示一个println,说明用户尝试获取数字的次数。
import java.util.*;
public class prog210c
{
public static void main()
{
Scanner sc = new Scanner(System.in);
Random rn = new Random();
int randomNum = rn.nextInt(90) + 10;
System.out.println("I am thinking of a number between 1 and 100");
while (true) {
System.out.print("What do you think it is? ");
int guess = sc.nextInt();
if(guess < randomNum)
{
System.out.println("Higher--Try Again");
}
else if(guess > randomNum)
{
System.out.println("Lower--Try Again");
}
else if(guess == randomNum)
{
System.out.println("Correct!");
break;
}
else
{
System.out.println("Enter a number between 1 and 100");
}
}
//System.out.println("You got it right in " + + " guesses");
} //end main
} //end class
答案 0 :(得分:1)
只需创建一些int变量来存储您的尝试次数,并在每次猜测时递增它。
int attempts = 0;
System.out.println("I am thinking of a number between 1 and 100");
while (true) {
System.out.print("What do you think it is? ");
int guess = sc.nextInt();
attempts++;
/**
* The rest of your loop code here.
*/
}
System.out.println("You got it right in " + attempts + " guesses");
答案 1 :(得分:0)
执行此操作的最简单方法是声明一个计数器整数,并在每次用户尝试时以逻辑递增。
int guessCounter = 0;
while(true) // Also do not use an infinite while loop, have an expression that can be terminated
{
...obtain input
if(guess < randomNum)
{
...
guessCounter++;
}
else if (guess > randomNum){
....
guessCounter++;
}
System.Out.println("The number of attempts " + guessCounter);
}
答案 2 :(得分:0)
您可以通过创建变量来存储尝试次数(例如int
),然后在每次用户猜测时使用int
添加一个变量来执行此操作:
variable++
如果你想要超越,你可以做到这一点,它说你在1 猜测 而不是说你如果用户在第一次尝试时获得正确的数字,则在1 猜测 中做到正确。我们可以通过使用三元Java运算符来实现这一点,这是一个非常紧凑的if语句:
public static void main(){
Scanner sc = new Scanner(System.in);
Random rn = new Random();
int tries = 0;
int randomNum = rn.nextInt(90) + 10;
System.out.println("I am thinking of a number between 1 and 100");
while(true){
System.out.print("What do you think it is? ");
int guess = sc.nextInt();
//Rest of your code here
}
System.out.println("You got it right in " + tries + " guesses");
}
这正在做的是:String s = (tries == 1 ? "guess" : "guesses");
现在我们可以更改你正确的... 你的程序的一部分,如果用户说猜而不是猜猜在第一次尝试时猜测数字:
if this is true ? do this : else do this