我遇到的问题是单击嵌套列表项与单击列表中列出的列表项目相同。所以,如果我尝试一个console.log列表项使用jscript点击,我点击其中一个嵌套列表项,在列表中我会得到两个console.logs。第一个是您单击的实际列表项对象,第二个日志是保存无序列表的列表项。有办法解决这个问题吗?
基本上我希望用户能够点击具有下拉列表的列表项并加载页面,并使下拉列表下拉。当您单击下拉列表中的任何嵌套列表项时,内容将从该链接加载,然后下拉菜单将被隐藏。
请帮助解决这个问题非常有帮助。
这是HTML
<div class="menu">
<div class="toggle-btn visible-xs"><i class="fa fa-sort-desc fa-2x"></i></div>
<ul>
<li><a class="active-menu" attr="Retirementplans2" href="">Retirement Plans</a></li>
<li class="exty"><a class="nact subm" attr="nadart4kplans" href="">NADART 401(k) Plans<span class="caret"></span></a>
<ul class="sub-menu">
<li><a class="nact sub" attr="investmentChoicePlans" href="">Investment Choice Plans</a></li>
<li><a class="nact sub" attr="openArchitecturePlans" href="">Open Architecture Plans</a></li>
<li><a class="nact sub" attr="nadartsub20plans" href="">Sub20 Plans</a></li>
<li><a class="nact sub" attr="executiveplansolutions" href="">Executive Plan Solutions</a></li>
</ul></li>
<li class="exty"><a class="nact subm" attr="PlanDesign" href="">Plan Design<span class="caret"></span></a>
<ul class="sub-menu">
<li><a class="nact sub" attr="flexiblefreestructure" href="">Flexible Fee Structure</a></li>
<li><a class="nact sub" attr="EmployerMatchingOptions" href="">Employer Matching Options</a></li>
<li><a class="nact sub" attr="AutomaticEnrollment" href="">Automatic Enrollments</a></li>
<li><a class="nact sub" attr="Roth4kOption" href="">Roth 401(k) Option</a></li>
<li><a class="nact sub" attr="rai" href="">Retirement Accumulation Insurance</a></li>
</ul></li>
<li><a class="nact" attr="Fiduciaryservices" href="">Feduciary Services</a></li>
<li><a class="nact" attr="Understanding4kFees" href="">Understanding 401(k) Plans</a></li>
<li><a class="nact" attr="Makinga4kDecision" href="">Making 401(k) Decision</a></li>
<li><a class="nact" attr="MakingTheTransitionEasy" href="">Making the Transition Easy</a></li>
</ul>
</div>
这是脚本:
var submenu = function(){
var tglBtn = $(".toggle-btn"),
mc = $(".main-content"),
subnav = $(".sub-menu"),
subItem = $(".menu ul").find('li');
if(tglBtn.css('display') === 'block'){
$(".menu ul").find('li.nact').slideToggle();
}
tglBtn.on('click', function(){
$(".menu ul").find('li.nact').slideToggle();
});
if($(".toggle-btn").css('display') === 'block'){
subItem.on('click', function(e){
e.preventDefault();
$(".menu ul").find('li.nact').hide();
});
}
if(subnav.length >= 1){
subnav.find('li').hide();
}
var submenuNavigation = {
ajaxCall: function(e){
e.preventDefault();
var $this = $(this),
pageName = $this.attr('attr').toLowerCase(),
item = '_'+pageName+'.html',
subMenu = $this.find('ul').length;
$this.parent().find('li').removeClass('actLink');
console.log(item);
if($this.hasClass("subm")){
$this.next('ul').find('li').show();
$this.next('ul').find('a').show();
}
$.ajax('partials/'+item, {
url:location.pathname+pageName+' - NADART',
success: function(response){
mc.html(response);
$this.addClass('actLink');
location.hash = pageName;
},
error: function(){
alert("Page not available");
},
beforeSend: function(){
mc.addClass('.loading');
},
complete: function(){
mc.removeClass('.loading');
}
});//END OF AJAX CALL
},
subnav: function(){
//subnav.find('li').toggle();
}
};
//EVENTS
subItem.on('click', 'a', submenuNavigation.ajaxCall);
subnav.on('click', 'a', submenuNavigation.subnav);
};
$(document).ready(function(){
submenu();
mainItem();
});
答案 0 :(得分:0)
有两种方法可以做到这一点:
或