Question

我有一张桌子：

table1

id value date
1  2     2014-10-11 17:24:16
2  3     2014-10-12 13:24:16
3  2     2014-10-12 15:24:16
4  2     2014-10-12 17:24:16
5  4     2014-10-14 11:24:16
6  2     2014-10-14 13:24:16

我想得到以下结果：

value date
2     2014-10-11
7     2014-10-12
0     2014-10-13
6     2014-10-14

我如何在mysql中执行此操作？感谢。

P＆gt; S：该行在哪里： 0 2014-10-13 ？

Answer 1

尝试下面的内容：

SELECT SUM(value) AS value, DATE(date) As Date 
FROM Table
GROUP BY DATE(date)

Answer 2

SELECT SUM(value) AS value,  DATE(date) AS date
FROM table1
GROUP BY DATE(date)

Answer 3

试试这个

<?php
$a = mysqli_query($db, "SELECT SUM(value) AS value,  DATE(date) AS date, DAYOFMONTH(date) AS day FROM mytable GROUP BY DATE(date)");
WHILE($a2 = mysqli_fetch_array($a))
{
    if($daycheck == "")
    {
        $daycheck = $a2[day];
    }
    else
    {
        if(($daycheck + 1) != $a2[day])
        {
            for($x = ($daycheck+1); $x<$a2[day]; $x++)
            {
                $date_new2 = date('Y-m-d', strtotime($daycheck2 . ' + 1 day'));
                echo "0-----".$date_new2."<br>";
                $daycheck2 = $date_new2;
            }
        }
    }
    echo $a2[value]."-----".$a2[date]."<br>";
    $daycheck = $a2[day];
    $daycheck2 = $a2[date];
}
?>

这将显示结果中间没有日期的0值

Answer 4

为了做你想做的事，你需要生成你范围内的所有日期，然后使用left join。以下是一种方法：

select d.d, sum(t1.value) as value
from (select date('2014-10-11') as d union all
      select date('2014-10-12') as d union all
      select date('2014-10-13') as d union all
      select date('2014-10-14') as d
     ) d left join
     table1 t1
     on date(t1.date) = d.d
group by d.d
order by d.d;

Answer 5

SELECT sum(value) as value, DATE(date) FROM <table> GROUP BY DATE(date)

Answer 6

尝试此查询：

Select sum(value), DATE(`date`) from table1 group by DATE(`date`)

Answer 7

试试这个

SELECT SUM(value) AS value,
       DATE(date) AS date
FROM table1
GROUP BY DATE(date)

Answer 8

你必须使用分组

select sum(value) ,DATE_FORMAT(date,'%Y-%d-%m') as date from MyTable group by DATE_FORMAT(date,'%Y-%d-%m')

DEMO

来自mysql分组的请求按日期与差距

8 个答案: