Question

我基本上有以下代码：

LinkedList<int>[] listOfNumbers = new LinkedList<int>[6];
int[] someNumbers = new int[6];

for(int index = 0; index < 6; index++)
{
  listOfNumbers[index] = new LinkedList<int>();
}

someNumnbers[0] = 0;
someNumnbers[1] = 1;
someNumnbers[2] = 2;
someNumnbers[3] = 3;
someNumnbers[4] = 4;
someNumnbers[5] = 5;

for(int index = 0; index < 6; index++)
{
  listOfNumbers[index].AddLast(someNumbers[index]);
}

我希望在最后一个循环的第一次传递后来自Visual Studio中的对象监视工具的以下报告：

listOfNumbers[0] has 1 element with value 0
listOfNumbers[1] has no elements
listOfNumbers[2] has no elements
listOfNumbers[3] has no elements
listOfNumbers[4] has no elements
listOfNumbers[5] has no elements

但我很好奇地发现了这个：

listOfNumbers[0] has 1 element with value 0
listOfNumbers[1] has 1 element with value 0
listOfNumbers[2] has 1 element with value 0
listOfNumbers[3] has 1 element with value 0
listOfNumbers[4] has 1 element with value 0
listOfNumbers[5] has 1 element with value 0

当我运行最后一个循环到完成时，我得到以下内容：

listOfNumbers[0] has 6 element with values 0,1,2,3,4,5
listOfNumbers[1] has 6 element with values 0,1,2,3,4,5
listOfNumbers[2] has 6 element with values 0,1,2,3,4,5
listOfNumbers[3] has 6 element with values 0,1,2,3,4,5
listOfNumbers[4] has 6 element with values 0,1,2,3,4,5
listOfNumbers[5] has 6 element with values 0,1,2,3,4,5

与我期望的结果相比：

listOfNumbers[0] has 1 element with value 0
listOfNumbers[1] has 1 element with value 1
listOfNumbers[2] has 1 element with value 2
listOfNumbers[3] has 1 element with value 3
listOfNumbers[4] has 1 element with value 4
listOfNumbers[5] has 1 element with value 5

我的第一个猜测是我在语法中写了一些不正确的东西，但我似乎无法弄清楚是什么。显然，似乎每次传递都会将AddLast（）应用于列表数组中的每个列表，但我不知道为什么。任何帮助将不胜感激。

Answer 1

我想你正在制作一个LinkedLists数组，而你只想使用LinkedList。

尝试将其初始化为单个LinkedList，然后添加元素。

查看文档中提供的LinkedList<T>类的使用示例： http://msdn.microsoft.com/it-it/library/he2s3bh7(v=vs.110).aspx

Answer 2

您应该尝试使用两个for循环执行以下操作。外循环用于遍历每个列表，内循环用于填充每个列表。

for(int i=0; i<6;i++)
{
for(int index = 0; index < 6; index++)
{
  listOfNumbers[i].AddLast(someNumbers[index]);
}
}

Answer 3

如果你在每个索引中都有相同的链表实例，如果你实际上正在初始化链表数组，就会发生这种情况，因为你已经证明它不应该是一个问题。同一个实例意味着你将一个链表实例化为一个变量，然后在每个数组索引中分配，这基本上意味着因为它们在内部都是相同的对象，无论你调用addlast方法在哪个对象中，它会反映在数组中的每个项目中。

AddLast（）在一个列表中添加到列表C＃中的所有列表

3 个答案: